vector<int> arr(100);//整型的array數組 int main() { arr[20] = 50;//其餘都是默認值0 vector<int>::iterator s = find(arr.begin(), arr.end(), 50);//第一個參數是array的起始地址,第二個參數是array的結束地址,第三個參數是需要查找的值 if (s != arr.end())//如果找到,就輸出這個元...
3.remove() std::vector没有直接删除特定值元素的成员⽅法。所以必须使⽤remove算法: std::vector Elem coll; //remove all elements with value val coll.erase(remove(coll.begin(), coll.end(), val), coll.end()); remove()返回的是删除后的尾部迭代器,必须调⽤erase()显式地删除其后的元素。
inlinevoid deduplication(T& c) { sort(c.begin(), c.end()); T::iterator new_end = unique(c.begin(), c.end());//"删除"相邻的重复元素 c.erase(new_end, c.end());//删除(真正的删除)重复的元素 } int main() { int ary[] = {1 , 1, 2, 3 , 2, 4, 3}; vector<int> ve...
The code proceeds to find the elements in vector a that are not present in vector b using the setdiff() function. Finally, it prints "Elements of a that are not in b:" followed by the result, which shows the unique elements in a that do not appear in b.R...
C++ vector中实际删除元素使⽤的是容器vector中std::vector::erase()⽅法。C++ 中std::remove()并不删除元素，因为容器的size()没有变化，只是元素的替换。1.erase( ) 删除元素 函数原型：iterator erase (iterator position);//删除指定元素 iterator erase (iterator first, iterator last);//删除指定范围...
Print the result: Displays the result of the union operation: ("a", "b", "c", "d", "e", "f", "g"), which contains all unique elements present in either vector.
Example: Find Common Vector Elements If we want to identify all elements of our vectors, which are existent in each of the vectors, we can use a combination of the Reduce(),intersect(), and list() functions. Have a look at the following R code: ...
vector<int> myvector (myints,myints+8); std::vector<int>::iterator it; // using default comparison: it = std::adjacent_find (myvector.begin(), myvector.end()); if (it!=myvector.end()) std::cout << "the first pair of repeated elements are: " << *it << '\n'; //...
Thank´s... What i need is something more complex, but i didn´t explain it... If i find 2 iqual elements like number 1, for example, what i need to do is connect the other elements in the same line. If i find 1 in to lines ([1 2] and [6 1]) what i need to do ...
// find_end example #include <iostream> // std::cout #include <algorithm> // std::find_end #include <vector> // std::vector bool myfunction (int i, int j) { return (i==j); } int main () { int myints[] = {1,2,3,4,5,1,2,3,4,5}; std::vector<int> haystack (my...