Find the vector equation of line passing through A(3, 4, -7) and B(1, ... 02:40 Consider the line L(1) : (x-1)/(2)=(y)/(-1)=(z+3)/(1), L(2) : (x-4)/(1... 02:23 Find dy/dx if ax-by=sinx 01:01Exams...
Find the vector equation o the line passing through (1,2,3) and parallel to the planes vecr.(hati+hatj+2hatk)=5 and vecr.(3hati+hatj+hatk)=6
Answer to: Find the vector equation of the line through the point (4,8,8) parallel to the vector [3,4,8]. By signing up, you'll get thousands of...
Find the vector equation of the line intersection of the following two planes: 4 x + 3 y - 2 z + 7 = 0 and x - 2 y + 5 z - 1 = 0. Find the vector equation for the line of intersection of the planes 3x - 3y - z = 2 and 2z = -2. ...
First of all find the required vector v which is passing through points (a0,b0,c0) and (a1,b1,c1) by using the formula v=⟨a1−a0,b1−b0,c1−c0⟩. Parametrization is done with the help of parameter t by using the equation x=a0+vt,y=b0+vt,z=c0+vt...
:Find the equation of each of these lines in vector form.(1)Through (2,4_.}-1) in the direction($$ \frac { 3 } { 6 } $$ (2) Through (1,0,-1) in the direction (3).$$ r=(^{2})+n(\frac{3}{4}) \overrightarrow{r}=(o^{1}_{-1})+ \lambda(o) $$(3)Through...
题目【题目】Find the vector equation of the plane which go es through the point (0,1,6) and is parallel to t he plane r.$$ ( i - 2 j ) = 3 . $$ 相关知识点: 试题来源: 解析 【解析】 r.$$ ( i - 2 j ) = - 2 $$ ...
Answer to: Find the equation of the line through the point (2, 1, 3) and perpendicular to the vectors u = 2 i - j + k and v = 3 i - 2 j + 5 k. By...
The point through which the line passes is given as (1,−2,3). We can denote this point as a position vector:a=1^i−2^j+3^kThe direction vector of the line, which is parallel to the given vector, is:b=3^i−2^j+6^k Step 2: Write the vector equation of the lineThe ...
If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)/2and (x-1)/(3k)=(y-1)/1=(z-6... 02:07 Find the vector equation of the line passing through (1, 2, 3) and ... 01:44 Write the vector equation of the plane, passing through the point (a ,... 02:43 Find the shortes...