百度试题 结果1 题目Find the value of k for which y=6x+k is a tangent to the curve y=7√x一道求切线的数学题 THX 相关知识点: 试题来源: 解析 在切点的斜率是6,先算出切点坐标,在得到k=49/24 反馈 收藏
解析 (k+1)x^2+2(k+3)x+(k+8)=0 f(x_1∈_9y_2c_200+x_3^2-4Ac=0 ⇒(2(k+3))^2-4(k+1)(k+8)=0 4/4(k+3)^2=4/4(k+1)(k+8) k^2+6k+9=k^2+9k+8 -1^2-6k-8⋅-1^2-6k-8 1=3K⇒|k=1/3
【题目】Find the set of values of k for which the equation z2+ 2z+ 11 = k(2z-1) hastwodistinct real roots(6 marks)korkSubmit AnswerSkip for Now 相关知识点: 试题来源: 解析 【解析】PrawerHence,tuevaluesofkshould be 5k-2 反馈 收藏 ...
Find the set of values of k for which the equat Onx^2+2x+11=k(2x-1)hantwodistinct real roots(6 marks)orSubmit AnswerSkip for Now 答案 AMAOC_2° Hence,thevalue_x0y Δhθu/dA be5Lk-相关推荐 1Find the set of values of k for which the equat Onx^2+2x+11=k(2x-1)hantw...
(a) Find the range of values of k for which 3x^2+8x+k is always positive. 相关知识点: 试题来源: 解析 (a)5{{1}\over{3}} %" font-base="12" style="font-style: normal; font-variant-caps: normal; font-weight: 400; white-space: normal; font-variant-ligatures: none; font-size...
Find all values of k for which the matrix (bmatrix) k-1&1&2 0&k-2&1 0&0&k-3(bmatrix) is not invertible. ( ) A. k=1 only B. all k≠q 1 C. k=1, 2 or 3 D. k=0 only E. All k≠q 2 相关知识点: 试题来源: ...
百度试题 结果1 题目【题目】Find the values of x for which the following converge:k=1 相关知识点: 试题来源: 解析 【解析】Convergesabsolutey for x ∈]-1,1[Diverges at x=-1Converges conditionaly at x=1 反馈 收藏
Find the value of k that makes the function f(x) = \left\{\begin{matrix} kx-1 & x \lt 2\\ (3-x)^2+1 & x \geq 2 \end{matrix}\right. continuous. Find values of x if any, at which f(x)= \frac{x^2 + 8x + 16}{|x| + 4} is not continuous. ...
Find the values of x for which the series converges. Find the sum of the series for those values of x: ∑n=1∞(−5)nxn. Geometric Series: The ratio between consecutive terms in a geometric series is constant. We can ...
【题目】4. Find the maximum value of ro for which there exists a sequence x, x, …, xi9s ofpositive reals with(i) x_0=x_(1995)x_(i-1)+2/(x_(i-1))=2x_i+1/(x_i) for i=1,..,1995.(POL)4.设正实数数列x,x,…,x1满足以下两个条件(i) x_0=x_(1595)() x_(i-1)...