aFind the equation of the tangent to the curve 4x2 + 3y2 = 7 at the point (1,1) . 发现正切的等式对曲线4x2 + 3y2 = 7在点 (1,1) 。[translate]
x=tcos t, y=tsin t; t=π t=π , t=π , and t=π . When t=π, (x,y)=(-π ,0) and (x,y)=(-π ,0), so an equation of the tangent to the curve at the point corresponding to t=π is y-0=π [x-(-π )], or y=π x+π ^2.反馈...
Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter., ; t=1 答案 , ; t=1. , , and .When t=1, (x,y)=(0,2) and , so an equation of the tangent to the curve at the point corresponding to t=1 is y-2=1(x-0) or...
2.Find the equation of the tangent to the curve y=x2-2x which is perpendicular to the line 2y=x-13.Find the equation of the normal to the curve y=3x2-2x-1 which is parallel to the line y=x-3 答案1:找到平行于X轴的曲线切线方程Y = X^ 22:找到的垂...
本人在国外读a levelfind the equation of the tangent to the curve y=x2-2x which is prependicular to the line y=x-3说错了 是这一题 find the equation of the normal to the curve at te point with the given x-coordinate y=1-x2 where x=0
Find the equation of the tangent to the curve given by {eq}2(x^2 +y^2 )^2 = 25(x^2 -y^2 ) {/eq} at the point {eq}(3,1). {/eq} Tangent to a curve Given a curve with equation {eq}F(x,y) = 0 \text{ and } y' = \frac{dy...
百度试题 结果1 题目 5. The equation of a curve is given by y-2x3y=3. Find the equation of the tangent to the curve at y=1. 相关知识点: 试题来源: 解析 5.7y=18x+25 反馈 收藏
31.Find the equation of the tangent to the curve y=x2,which is parallel to the x-axis2.Find the equation of the tangent to the curve y=x2-2x which is perpendicular to the line 2y=x-13.Find the equation of the normal to the curve y=3x2-2x-1 which is parallel to the line ...
Also, find the point of tangency at the given parameter. Answer and Explanation:1 To find the tangent line to any curve(x,y)=(x(t),y(t), we find its slope which isdy/dxor {eq}\; ... Learn more about this topic: Tangent Line |...
The tangent to a curve is a straight line that touches the curve at a certain point and has exactly the same slope as the curve at that point. There will be a different tangent for each point of a curve, but by using calculus you will be able to calculat