Find the position vector of a point R which-divides the line joining two points P and Q whose position vectors areˆi+2ˆj−ˆkand−ˆi+ˆj+ˆkrespectively, in the ratio 2:1 Internally View Solution Find the position vector of a point R which-divides the line joining two...
百度试题 结果1 题目 Find the position vector of the point of intersection of each of these pairsof lines.x=(2/1)+λ(1/0)_(0.1)) 相关知识点: 试题来源: 解析 4;-1;1;. 反馈 收藏
Find the position vector of a particle that has the acceleration {eq}\mathbf a(t) = 11t \mathbf i + e^t \mathbf j + e^{-t} \mathbf k, {/eq} and initial velocity {eq}\mathbf v(0) = \mathbf k {/eq} and position {eq}\m...
<p>To solve the problem, we need to find the position vector of point R, which divides the line segment joining points P and Q externally in the ratio 1:2. We also need to show that point P is the midpoint of segment RQ.</p><p><strong>Step 1: Identify th
Question: Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t) = 12ti + sintj + cos2tk, v(0) = i, r(0) = j I got (2t^3+t)i+(t-sint+1)j+(1/4-(cos2t)...
Given that the plane contains line r= i+ j+λ ( i +2 j- k) and point A (-1,3,-4).Hence, the point b = i+ j and the vector c = i +2 j- k lies on the plane.If the co - ordinates of a point A (x_1,y_1,z_1), then the position vector of A(a ) isa=x_...
试题来源: 解析 To find the position vector, subtract the initial pointvector( P) from the terminal pointvector( Q). ( Q-P=(1i+2j)-(0i+0j)) Simplify each term. ( i+2j+0) Add ( i+2j) and ( 0). ( i+2j) 反馈 收藏 ...
Our methodology begins by formulating a vector differential equation, leveraging the unit principal normal vector of a general helix with the assistance of the alternative moving frame. Then, by solving this differential equation, we obtain the position vector of the general h...
Answer to: The position vector of a particle is r (t). find the requested vector. The velocity at t = 0 for r(t) = In( t^3-3t^2 + 1)i-...
Find {eq}\vec{r}(t) {/eq} that satisfies the following conditions: {eq}\frac{d \vec{r}(t)}{d t} = <\frac{1}{1+ t^2},\frac{1}{t^2},\frac{1}{t}>\\ \vec {r}(1) =<2,0,0> {/eq} Vectors: In the given problem, we use...