According to the problem, we have a series given as 1, 3, 5, 7, 9,……. We need to find the sum of the elements in this series up to n terms.We know that an Arithmetic Progression (AP) is of form a, a+d, a+2d,…….., where ‘a’ is kno...
*/ import java.util.Scanner; import java.util.Set; import java.util.TreeSet; /** * * @author abhishek87 */ class APTripletInStream { public static void main(String[] args) { int idx=0, numInStream; Scanner scanIn = new Scanner(System.in), readLine; String line = scanIn.nextLine(...
百度试题 结果1 题目【题目】Find the first three terms in the expansion inacenn osoo ap 相关知识点: 试题来源: 解析 【解析】1+5x+6x^2
Sum of first n terms (Sn) = (n/2) * [2a + (n-1)d] Where: Snis the sum of the arithmetic progression's first n terms. nis the number of terms in the progression. ais the first term of the progression. dis the common difference between consecutive terms. ...
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So the series of natural numbers is 1, 2, 3,……….200. Here the first term a is 1. Common difference d is also 1 clearly. Last term( l ) is 200. Number of terms is also 200. We know the sum of n terms of an AP can be written as ${{\text{S}}_{\text{n}}...
. For each day start at the diagonal (must always be 0) and fill in the columns to the right, one day at a time. If you land on a weekend day (non business day) column, the number of business days doesn't change, it is carried from the left. Otherwise, the number of bu...
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Four numbers are in A.P. The sum of these numbers is 50 and the greatest number is 4 times the least. To do: We have to find the numbers. Solution: Let the first three terms of the AP be a−3d,a−d,a+d,a+3da−3d,a−d,a+d,a+3d....