Find the number of terms common to the two AP's 3,7,11,15.... 407 and 2, 9 ,16.......709. View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage
Solution: Given, the series consists of 37 terms. Sumof three middle most terms = 225 Sum of last three terms = 429 We have to find theAP. Number of terms, n = 37 is odd Middle term = (n+1)/2 th term = (37+1)/2 = 38/2...
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We know that, in an AP the sums of the terms equidistant from the beginning and end is always same and is equal to the sum of first and last term. Then, t(1) + t(24) = t(5) + t(20) = t(10) + t(15) but given t(1) + t(5) + t(10) + t(15) + t(20) + t(...
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