(a) Find the number of different arrangements which can be made of all 10 letters of the word WALLFLOWER if(i) there are no restrictions, [1](ii) there are exactly six letters between the two Ws. [4](b) A team of 6 people is to be chosen from 5 swimmers, 7 athletes and 4 ...
To solve the problem of finding the number of arrangements that can be made out of the letters of the word "algebra" without altering the relative positions of vowels and consonants, we can follow these steps:Step 1: Identify the vowels
Find the number of arrangements of the letters of the word SALOON, if the two Os do not come together. View Solution Find the number of arrangements of the letters of the word "Delhi" if e always comes before i. View Solution Find the number of arrangements of the letters of the word...
6.(a)(Ten points are marked on the circumference of a circle. Find the number of triangles that can be formed.[1](b) Twelve points are marked on the circumference of a circle and labelled with digits from 1 to 12. Find the number of possible arrangements such that points labelled with...
Find the total number of possible arrangements of 3 letters chosen from the word CALCULUS.中文意思是:从单词CALCULUS中选出3个字母进行排列,找出总共有多少种可能的排列方法 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 CALCULUS这个词共有5种字母,分别是CALUS然后三个字母进行排列的...
结果1 题目 (b) Find the number of different arrangements of the 9 letters in the word CELESTIAL in which the first letter is C. the fifth letter is T and the last letter is E.[2]360 相关知识点: 试题来源: 解析 360 反馈 收藏 ...
Step by step video, text & image solution for Find the number of arrangements of the letters of the word INDEPENDENCE. In how many of these arrangements, do the words start with P . by Maths experts to help you in doubts & scoring excellent marks in Class 11 exams.Updated on...
Find the number of arrangements of the letters of the word INDEPENDENCE. In how many of these arrangements. do the vowels never occur together View Solution How many diferent words can be formed with the letters of the word MATHEMATICS ? In how many of them, vowels are together and consonant...
Arrange the 7 letters CTEPILL = 7! 2! Number of ways of placing As in non-adjacent places = -"C. Total arrangements with R at beg, andcnd=(9!)/(2!2!) Arrangements with R at ends and As together= With As not together [90720-20160]=70560xk seen. k an integer 1. m*n(n-1...
You need to know the number of different arrangements possible for five distinct letters. You decide to use the permutations rule, but your friend tells you to use 5!. Who is correct? Explain. - Neither method is correct. The ...