The normal vector of a plane in space is perpendicular to any line in the plane. This normal vector is also perpendicular to the normal vector of any other plane orthogonal to this plane. Answer and Explanation: This line with the vector equation {eq}...
{y_0},{z_0}} \right){\text{ that is on the plane and a normal }} \cr & {\text{vector }}\,\vec u = \left\langle {a,b,c} \right\rangle {\text{ (perpendicular to the plane)}}{\text{. So}}{\text{, knowing the point }}P{\text{ and ...
Consider the plane which passes through the three points: {eq}(-7, -3, 10), (-10, -7, 13), {/eq} and {eq}(-10, -6, 15) {/eq}. Find the vector normal to this plane which has the form: {eq}(11...
The unit normal vector^nis given by: ^n=n|n|=2^i−3^j+4^k√29 Step 4: Write the vector equation of the plane The vector equation of a plane can be expressed as: r⋅^n=d Substituting the values we have: r⋅(2^i−3^j+4^k√29)=6√29 ...
Find the vector equation of a plane which is at a distance of 7 units from the origin and normal to the vector 3ˆi+5ˆj−6ˆk. A6√70 B5√70 C8√70 D7√70Submit Find the vector equation of a plane which is at a distance of 6 units from the origin and has 2, -1, ...
百度试题 结果1 题目(1) Find the vector equation of a plane which is at 42 unit distance from the origin and which is normal to the vector 2i+ j-2k. 相关知识点: 试题来源: 解析 ·(2i+j-2k)=126 反馈 收藏
Hence, point P(0, 5, 2) is a point on the line of intersection.A is a given point (-2, 3, 3), vector AP = (2, 2, -1)The vector of the normal direction of the plane required= N cross times AP= (4, -9, -5)×(2, 2, -1) = (19, -6, 26)Sub (19, -6, 26) ...
I have a question about converting normal vector components of a plane into dip and dip direction. I have a txt file containing multiple colums and three of than being nx, ny, and nz? Can you please help me on how to find a dip direction and a dip of a pla...
Learn how to find the magnitude of a vector. Then, using a vector's direction and magnitude, learn how to create a vector and magnitude graph with...
Let r(t) be a differentiable vector valued function and v(t)=r(t) be the velocity vector. Then we define the unit tangent vector by: T(t)=v(t)‖v(t)‖ Unit Normal Vector: Let r(t) be a differentiable vector valued function and let T(t) be the unit tangent vector. Then the...