这是一个Java程序,用于解决LeetCode题目中的“Find the Missing Number”问题。该程序的主要功能是在一个给定的整数数组中找出缺失的数字。 具体实现过程如下: 1. 首先,创建一个名为`findMissingNumber`的方法,该方法接收一个整数数组作为参数。 2. 然后,遍历数组中的每个元素,将其与数组长度减一的结果进行比较。
Find the Missing Number 方法一: 数学方法,先找到最大的值,需要比较最大的值和array size, 要是比array size小, 说明最大值missing。 然后用等差数列公式求得如果不缺失值的和,然后再减去array里数的和。 classSolution {public:/** * @param nums: a vector of integers * @return: an integer*/intfin...
We are given a list of n-1 integers and the integers range from 1 to n. There are no duplicates in the list. Only one of the integer from 1 to n is missing. We need to find the missing number in O(n) time complexity.SolutionThe simplest solution is to take each number from 1 ...
百度试题 结果1 题目Find the missing number: ( ) . A: B: C: D: 相关知识点: 试题来源: 解析 C , so choice is correct. 找出缺失的数:( ). . . . . ,所以()选项是正确的. 故选.反馈 收藏
In this Java puzzle, we have a series of numbers and exactly one number is missing. We have to write a program to find the missing number.
Develop fluency with addition by balancing addition problems and finding the missing numbers in this worksheet.
[LintCode] Find the Missing Number http://www.lintcode.com/zh-cn/problem/find-the-missing-number/# 先做一轮桶排序,把每个元素放在它应该在的位置上(只要nums[i] != i并且nums[i] < n,就执行交换:swap(nums[i], nums[nums[i]]),注意nums[i] < n的条件不能漏掉,否则交换会导致数组越界访问...
百度试题 结果1 题目Find the missing number!相关知识点: 试题来源: 解析 (1)6,4;(2)2,2;(3)7,4 (1) 4 6 + 4 3 8 9 (2) 2 8 + 5 4 1 8 2 (3) 6 7 - 4 4 2 3 反馈 收藏
Find the missing number in the sequence:3,6,11,20,37,___,135.Answer:___. 相关知识点: 试题来源: 解析 70 70 因为6=3×2-0;11=6×2-1;20=11×2-2;37=20×2-3;所以下个数应该为:37×2-4=70;验证:70×2-5=135正好是最后一个数;故答案为:70 反馈 收藏 ...
Given an array containsNnumbers of 0 ..N, find which number doesn't exist in the array. Example GivenN=3and the array[0, 1, 3], return2. Challenge Do it in-place with O(1) extra memory and O(n) time. 这道题是LeetCode上的原题,请参见我之前的博客Missing Number 丢失的数字。那...