首先计算相邻项的差值:6-3=3,11-6=5,20-11=9,37-20=17。这些差值构成新的数列3,5,9,17。观察差值的差值:5-3=2,9-5=4,17-9=8,可以看出这里是公比为2的等比数列。下一个二次差应为16(8×2),则下一个一次差为17+16=33,因此空缺数为37+33=70。验证后续差值:下一个二次差32(16×2),对应一次...
Find the missing number in the sequence:3,6,11,20,37, 70,135.Answer: 70. 相关知识点: 试题来源: 解析 解:因为6=3×2-0;11=6×2-1;20=11×2-2;37=20×2-3;所以下个数应该为:37×2-4=70;验证:70×2-5=135正好是最后一个数;故答案为:70 观察可以发现6=3×2-0;11=6×2-1;20...
（37×2-4）我这样算：3×2-0=6 6×2-1=11 11×2-2=20 20×2-3=37 37×2-4=70 70×2-5=135 答案绝对是70，望采纳！
This sequence is increasing by 2 each time:- 1 (1st term)- 3 (2nd term)- 5 (3rd term)- 7 (4th term) Following this pattern, the next non-2 difference should be 9. Step 5: Calculate the next number in the seriesThe last number in the series is 26. To find the next number, ...
To find the missing number in the series 7, 10, 14, ?, 25, 32, we can follow these steps: Step 1: Identify the pattern in the seriesWe notice that the numbers are increasing. To understand how they are increasing, we should look at the differences between consecutive terms. Step 2:...
10. Find(a) the missing number in the sequence1,3,6,...,15,21,28,Answer. (a) 10 [1](b) an expression, in terms of n, for the nth term of the sequence5,9,13,17,21,...Answer:(b) 4n+1 [1] 相关知识点: 试题来源: 解析 104n+1 反馈...
Find the missing number in the pattern. 根据规律,找出横线上的数字. 1,3,5,7, ,12,16,18,23,25….相关知识点: 试题来源: 解析 10 1+2=3,3+2=5,5+2=7,12+4=16,16+2=18,18+5=23,23+2=25⋯.. 由此可得规律,第奇数个数与第偶数个数之间的差值规律为:2,2,3,2,4,2,5,2,6,2...
classSolution(object):defmissingNumber(self, nums):""":type nums: List[int] :rtype: int"""n=len(nums)returnn * (n + 1) / 2 - sum(nums) 看到一个很牛逼的方法 在原始数组上,把A[i] 调整到其原来的位置 是的A[i] = i ,结束的地方就是当A[i] <0 此题目没有负数也没有影响的,A...
10 . 30 . 15 18 . 10 . 5 6 . 3 . 9
回答和翻译如下:找到正在失去的号码，3，5，8，13，22。英语句子翻译。