Find the maximum and minimum values of the objective function f(x, y) and for what values of x and y they occur, subject to the given constraints.f(x,y)=2x-y 答案 8 at (4,0);-8 at (0,8) 相关推荐 1Find the maximum and minimum values of the objective function f(x, y) and...
所以最小值为2√2.因为x趋于0时,x+2/x趋于无穷大,所以没有最大值结果一 题目 关于求最大值 和最小值的问题Find the maximum and minimum point and values for the function on the given interval(x2+2)/x on (0,5】 答案 (x2+2)/x = x+2/x≥2√x×2/x =2√2 当x=2/x 时取等号 ...
解析 The maximum and minimum values of over the feasible region are and respectively.反馈 收藏
1 三角函数问题Find the maximum and minimum values of the function.(Round your answers to two decimal places.)y = 3x - 4sin 3x,0小于或等于x小于或等于2π\5(minimum)\5(maximum) 2【题目】三角函数问题Find the mazimum and minimum values of the function.(Round your answers to two decimal...
三角函数最大值和最小值Find the maximum and minimum values of the function.(Round your answers to two decimal places)y = 8x - 3sin 4x,x在0-2pi之间!急 相关知识点: 试题来源: 解析 第一个,x=2kπ,k∈Z,时有最大值,最大值为1 1=2.x=kπ,k∈Z,时有最小值,最小值为-1 1=0.第二...
So, the minimum of the array is -1 and the maximum of the array is 35. Thus, doing the same using multiple methods in C programming is as follows: Using Standard Method Read the entered array size and store that value into the variable n. ...
Answer to: Find the maximum and minimum distance from the origin to a point on the curve 9 x 2 2 x y + 9 y 2 = 6 in the ( x , y ) plane. By...
Use the Extreme Value Theorem to find the maximum and minimum values of on the interval [0,3]. ( )A. Max: 2 Min: -4B. Max: 2 Min: 1C. Max: 2 Min: -1D. Max: 2 Min: -2E. None of these 答案 D相关推荐 1Use the Extreme Value Theorem to find the maximum and minimum values...
1Activities all take place___the guidance of an experienced tutor. 2Find the maximum and minimum values of thefunction.y=cosx+sin2x 3 Many people complain of the rapid ___ of modern life. ratepacespeedgrowth 4She spoke with us under the help of an interpreter.___. 反馈 收藏...
Thus, the maximum value is 1 (attained at both x = - and x = 1), and the minimum value is -4 (attained at x = 2). The graph of fis shown in Figure 7. 4 y=-2x^1+3x^(-1) 4 -】 2 3 -1+ -2 Figure 7 EXAMPLE 1] Find the critical points f(x)=-2x^3+3x^2on[...