I assumed what you meant was two points of intercepts with x- and y-axis. If that is correct, you can find the line equation as follow. Step 1. Find the line's gradient Recall that the general equation for a line is: y = mx + c where m is the line's ...
How can I find the line equations corresponding to a line through two 3D points?The pair of equations are not unique, but one particular selection of them can be obtained as follows, with P=[xp,yp,zp].' and Q=[xq,yq,zq].',Here...
You need to find the equation of line l to write the equation of the perpendicular line that passes through P.结果一 题目 In Step 1, why do you need to find the equation of line ?Line contains points at and . Find the distance between line l and point .Step1 Find the equation of ...
1Find the equation of the line that passes through thefollowing points (a, b) and (a, b + 1) 2Find the equation ofthe line that passes throughthe following pOintsin(a,b)and(a,b+1) 3【题目】Find the equation of theline that passesthroughthe following point: (a, b)and (a, ...
Find the equation of the line in slope-intercept form. The line through (−1,−2) with slope −16 Slope-Intercept Form: In finding the slope-intercept form equation of a line, we first need to identify the slope and a point of the line. If two points of the...
Step 7: Find the slope of the line from the origin to the point of intersectionThe origin is (0,0) and the point of intersection is (3,1). The slope m of the line joining these two points is given by:m=y2−y1x2−x1=1−03−0=13 Step 8: Write the equation of the lin...
Answer to: Find the equation of one line that is tangent to the graph of f (x) = x (x -1)(x - 3)(x - 6) at two different points. Graph both...
Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? 答案 e是常数,f'(x)=1/x,所以切线在x=1点的斜率是1,在x=1点的函数值是e.So the equation of the tangent line of graph at x=1 is f(x)=x+e-1相关推荐 1Find the equation of line tangent to the grap...
Find the equation of the tangent line at x=2 for f(x)=√((4x+1)/(5x-1))100分题, 答案 定义域为D={x|x=1/5}导数f'(x) =-9/[2*(5x-1)²*√((4x+1)/(5x-1)) ]f'(2)=-1/18f(2)=1在点(2,1),函数的切线的斜率为-1/18,切线方程为 y-1=-1/18 *(x-2)整理,...
If we have two points, we use the slope formula {eq}m = \dfrac{y_2-y_1}{x_2-x_1} {/eq}. Then, with the formula slope point {eq}y - y_0 = m (x - x_0) {/eq}, we substitute the slope and a point, finding the equat...