To calculate the LCM of 10, 15, and 25 by thedivisionmethod, we will divide the numbers(10, 15, 25) by their prime factors (preferably common). The product of thesedivisorsgives the LCM of 10, 15, and 25. Step 1:Find the smallest prime number that is a factor of at least one o...
LCM of 10 and 50 is the smallest number among all common multiples of 10 and 50. The methods to find the LCM of 10, 50 are explained here in detail.
结果1 题目1. Find the sum of all odd numbers from 1 to100 that are not divisible by 11.(3 point, 2 min) 相关知识点: 试题来源: 解析 1. Find the sum of all odd numbers from 1 to100 that are not divisible by 11.2225(3 point, 2 min) ...
百度试题 结果1 题目8 Find the sum of all the integers between 300 and 600 that are divisible by 7. 相关知识点: 试题来源: 解析 19264 反馈 收藏
to write a definite loop—one that executes exactly 100 times. You can write a for loop that sets a variable to 1 and increments it to 100. Each of the 100 times through the loop, if 100 is evenly divisible by the variable, the application pr 假设您想要看到均匀地划分成100的所有数字。
To solve the problem of finding the smallest number which, when increased by 17, is exactly divisible by both 468 and 520, we can follow these steps:Step 1: Find the LCM of 468 and 520To find the least common multiple (L
Numbers divisible by 5 are 5,10,15,20,25...100. Now, we have to find the sum of these numbers⇒5+10+15+20...+100 can be written as⇒5(1+2+3+...+20)Using the formula, sum of first n numbers =n(n+1)2=5(20(21)2) =5×210=1050 Therefore, sum of integers which ...
What is the smallest positive integer n such that \sqrt{n} - \sqrt{n - 1} < 0.01 ? Find the smallest square number that is divisible by each of the numbers 8, 15, and 20. Find the smallest square number that is divisible by each of the numbers 4, 9, and 10. ...
结果1 题目 Let f(x)=4x3 kx 3, where k is a constant. If f(x) is divisible by 2x 1, find the remainder when f(x) is divided by x 1.( ) 设f(x)=4x3 kx 3,其中k为一常数.若f(x)可被2x 1整除,求当f(x)除以x 1时的余数.( ) A. −7 B. −6 C. 0 D. 5 ...
结果1 题目求使n^3能被n-2整除的整数n的数目.Find the number of integer n such that n^3 is divisible by n-2. 相关知识点: 试题来源: 解析 8.n^3=n^3-8+8=(n-2)(n^2+2n-4)+8即8能被n-2整除,题目即求8的因数数目,包括正和负因数共有8个. ...