Can you solve this real interview question? Find First and Last Position of Element in Sorted Array - Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value. If target is not found i
ThefindLastIndex()method does not change the original array. Array Find Methods: MethodFinds indexOf()The index of the first element with a specified value lastIndexOf()The index of the last element with a specified value find()The value of the first element that passes a test ...
Since the array is increasing first & then decreasing so the maximum element would be the last one in the increasing series & the first one in the decreasing series. SO we can ignore the increasing part and check if the next element is decreasing or not. As soon as we find...
To find the index of an element in an int array in Java, you can use the indexOf() method of the Arrays class. The indexOf() method returns the index of the first occurrence of the specified element in the array, or -1 if the element is not found. Here is an example of how ...
LeetCode-Find First and Last Position of Element in Sorted Array,LeetCodeJavaC++FindFirstandLastPositionofElementinSortedArray
Given an array of integersnumssorted in ascending order, find the starting and ending position of a giventargetvalue. Your algorithm's runtime complexity must be in the order ofO(logn). If the target is not found in the array, return[-1, -1]. ...
1. Problem Descriptions:Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value.If target is not found in the array, return [-1…
[LeetCode] 34. Find First and Last Position of Element in Sorted Array 在排序数组中查找元素的第一个和最后一个位置 Given an array of integersnumssorted in non-decreasing order, find the starting and ending position of a giventargetvalue....
=target){// 找到第一个与 target 相等的元素returnmid}high=mid-1}}return-1}// 二分查找最后一个与 target 相等的元素,时间复杂度 O(logn)funcsearchLastEqualElement(nums[]int,targetint)int{low,high:=0,len(nums)-1forlow<=high{mid:=low+((high-low)>>1)ifnums[mid]>target{high=mid-1}...
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