1.Find the gradient of the straight line that is perpendicular to the straight line with gradient equal to (a)2 (b)-3(c)-2/3(d)5/4 答案 反正相互垂直的线的gradient之和是等于-1的 所以,如果一条直线的斜率是2,那么和它垂直的那条直线的斜率就是-1/2 相关...
To find the gradient of the straight line that passes through the point (-3, 6) and the midpoint of the points (4, -5) and (-2, 9), we can follow these steps: Step 1: Identify the PointsLet point A be (-3, 6), point B be (4, -5), and point C be (-2, 9). Step...
1. (a) Find the gradient of the straight line passing through the points (1, 2) and (9, 10).(b) Given that the gradient of the straight line passing through the point (2, 3) is 5, find the equation of the line. 相关知识点: 试题来源: 解析 a)1b)y=5x-7 反馈 收藏 ...
<p>To solve the problem, we need to find the coordinates of points on a straight line with a given slope that are a certain distance away from a specified point. Here’s a step-by-step solution:</p><p><strong>Step 1: Identify the given information</stron
Find the gradient of the function {eq}\displaystyle g(x,y) = \frac{5y}{x^2 + 2} {/eq} at point (1,4). Then sketch the gradient together with the level curve that passes through the point. Gradient: ...
Find the gradient of L.(2)Find the coordinates of the point where L crosses the y-axis.(3)Find an equation of the line that is parallel to L and crosses the x-axis at (-2,0) 相关知识点: 试题来源: 解析 (1)1.5(2)(0,-7.5)(3)y=1.5x+3 (1)N/A.(2)N/A.(3)N/A....
The nonlinear least squares method minimizes the gradient of a criteria function. ForNmeasured data points{\left( X_i,p_i'\right) }, we have \begin{aligned} {\varvec{\alpha }}&={\left( K,\beta \right) }^\intercal ,\nonumber \\ r_i\left( {\varvec{\alpha }}\right)&=p'_i...
The diagram on the right shows a straight line graph.y Find the coordinates of the point on this line when y=r(24.53)(0.5)x Diagram not accurately drawn 相关知识点: 试题来源: 解析 So coordinates are (-5.-5)change in y Gradient change in x -(53-5)/(24-0)=(4k)/(24)=11 The ...
If the slope of a straight line through A(3,2) is 3/4. Then, the coordinates of the points on the line that are 5 units away from A is A(7,5) and (-1,-1) B(-7,-5) and (1,1) C(7,1) and (5,1) DNone of theseSubmitfind...
To find the distance between the straight line 4x+3y−5=0 and the point (−2,1), we can use the formula for the distance d from a point (x1,y1) to a line given by the equation Ax+By+C=0: d=|Ax1+By1+C|√A2+B2 1. Identify the coefficients from the line equation: The ...