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I assumed what you meant was two points of intercepts with x- and y-axis. If that is correct, you can find the line equation as follow. Step 1. Find the line's gradient Recall that the general equation for a line is: y = mx + c where m is the line's ...
The differentiation of the function can be easily found using the standard formula. There is another method to find the derivative, that is by the use of the first principle rule of differentiation, we need to use the concepts of limits ...
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Assembly: Microsoft.VisualStudio.ImageCatalog.dll Package: Microsoft.VisualStudio.ImageCatalog v17.13.40008 C++ 複製 public: static property Microsoft::VisualStudio::Imaging::Interop::ImageMoniker QuickFind { Microsoft::VisualStudio::Imaging::Interop::ImageMoniker get(); }; Property Value ImageMonike...
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Given the cash flow diagram below, determine the unknown value using an interest rate of 12%. Use a geometric gradient formula to compute the present value, P, for the following cash flows. If the interest rate is 10 percent and cash flows are $1,000 at the end of year one and $2,...
(omission of E_a)This mark subsumes gradient mark NOTE: Omission of E_a can get 1st 2marks ALLOW y=31.4ALLow substitution of correct values of In k and 1/Tinto lnk=-E_a/R*1/T+lnAto give a value of In A which approximately matches the intercept it given lnA -lnh+((E_a)/R+...
A stationary point of a curve is the point at which the gradient of the curve equals zero. Stationary points are important in physics and mathematics, notably in calculus. The stationary point of a function under consideration is the point where the derivative of the function is zero. If you...
(i) For finding the equation of a line, given its slope or gradient and its intercept on the y-axis, use slope-intercept form. (ii) To find the equation of a line, given its slope and coordinates of one point that lies on the line, use the point-slope form. (iii) For finding ...