题目13. Find the general term of the following linear sequence. a. 3, 8, 13, 18, 23, ... b. 13, 23, 33, 43, 53,... c. 2,9, 16, 23, 30,... d. 18, 16, 14, 12, 10,... 相关知识点: 试题来源: 解析 a. 5n-2b...
百度试题 结果1 题目Find the general term, u_n, of the geometric sequence that has:u_2=-12 and u_7=512 相关知识点: 试题来源: 解析 u_n=18(-4)^(n-1) 反馈 收藏
Finding the nth term of a sequence is easy given a general equation. But doing it the other way around is a struggle. Finding a general equation for a given sequence requires a lot of thinking and practice, but learning the specific rule guides you in discovering the general equation. In ...
百度试题 结果1 题目 In the following exercises, find a general term for the sequence whose first five terms are shown. 相关知识点: 试题来源: 解析 a_n=e^(n+2) 反馈 收藏
解析 Solution: (A). The general term of the sequence can be written as: a_n=2/(n(n+1)) which can be decomposed into two parts a_n=2(1/n-1/(n+1)) . Let n =1,2,3,… S_n=2(1-1/2+1/2-1/3+⋯+1/n-1/(n+1)) =2(1-1/(n+1))=(2n)/(n+1) ...
Solution: n.Method 1:Wkowtaf()=1+.From (46.4.2), we havea=a(++)×(+)×-x(1+吉)=1x×号Method 2:a.=(1+六)a can be written asan+1_ann+1neb=We ge the following new sequence[==1bn+1=bn(n=1,2,3,…)It is seen that {b } is a constant sequence with b =1.So2=...
For the sequence, 13, 24, 35, 46, ...the terms can be written as:a_1= 13= 1(1+2)a_2= 24= 2(2+2)a_3= 35= 3(3+2)a_4= 46= 4(4+2)From the general equation of the terms, substitute n to 1, 2, 3 and 4 to get the general term.Hence, the general term is:...
The general term of an of a sequence is −3n+4. (1) Find the 3rd term of the sequence. (2) If ar−a3=−12, find the value of r. 相关知识点: 试题来源: 解析 (1) a3=−3(3)+4 =−5 (2) (−3r+4)−(−5)=−12 r=7 (1)略(2)略...
1. Write down the general term of each of the following sequences in simplest form: So far I have been using guess and check to find the solutions, but it...
Find the general term of the sequence, starting with n = 1. 1, 1/5, 1/25, 1/125, ... Find the sum of the first 60 terms of the sequence. \{2, 10, 18, 26, ... \} Find the sum of the first 20 terms of the sequence 3, 7, 11, 15......