Describe the steps to find the equation of a line when given two points of intercept? Answer and Explanation: I assumed what you meant was two points of intercepts with x- and y-axis. If that is correct, you can find the line equation as follow. Step 1. Find...
Find the equations that represent a line segment between the points (1,5) and (3, 13). Find the line integral of \vec{F}(x,y,z)=x^{3\vec{i + y^{2\vec{j + z\vec{k} along the line segment C from the origin to the point (2,3,8). Find the line integral of F...
Answer to: Find the equation of the line that passes through (3, 3) and is perpendicular to y = 3x - 5. By signing up, you'll get thousands of...
will have a slope {eq}m = 2 {/eq} so we need to find the line {eq}y = 2x + b {/eq} that passes through... See full answer below. Learn more about this topic: Linear Equations | Definition, Formula & Solution from Chapter 1/ Lesson 3 ...
百度试题 结果1 题目【题目】Find the equations of the line parallel to Or and passing through the point of intersection of_(2y)-3x+4=0 and the y-axis. 相关知识点: 试题来源: 解析 【解析】y=-2 反馈 收藏
Differential Equations tutors AP Calculus tutors College Algebra tutors Algebra 2 tutors AP Calculus AB tutorsDownload our free app App Store Google Play Get to know us About Us Contact Us FAQ Reviews Safety Security In the News Learn with us Find a Tutor Request a ...
【题目】Find the parametric equations of the line through:(1)(1,2,1) and (-1,3,2)(2)c(0,1,3) and (31,-1)(3)(1,2,5) and (1,-1,5)(4) σ(0,1,-1) and 5,-1,3) 相关知识点: 试题来源: 解析 【解析】(1)x=1-2t,y=2+t,z=1+t, t∈R(2)x=3t,y=1,z=3-4t...
高数求切线和法线 find the equations of tangent line and normal line of the curve X的立方+Y的立方—3XY=0 at the point (2开根号下3次方,4开根号下三次方) 相关知识点: 试题来源: 解析 x^2+y^3-3*x*y=0 (x^2+y^3-3*x*y)'=0' 2*x+2*y^2*y'-(3*y'*x+3*y)=0 y'=(2*x...
但是此理论没有考虑破产成本。[translate] aFind the equations of the tangent plane and normal line to the given surface at the indicated point 发现切面和正常线的等式对特定表面在被表明的点[translate]
Find the equations of the tangent line and the normal line to the curve at the given point.6x^2+3xy+2y^2+17y-6=0,(-1,0) 答案 两边求导12x+3y+3xy'+4yy'+17y'=0y'=-(12x+3y)/(3x+4y+17)则过点(-1,0)的切线斜率为k=-[12*(-1)+3*0]/[3*(-1)+4*0+17]=12/14=6/7...