此解法的时间复杂度是O(n),空间复杂度是O(1)。 publicchar findTheDifference3(String s, String t) {intch=0;for (inti=0; i<s.length(); i++) {ch=ch^s.charAt(i);} for (intj=0; j<t.length(); j++) {ch=ch^t.charAt(j);} return (char)ch;} 05 第四种解法 此解法思路和第三...
java解法如下:public class Solution { public char findTheDifference(String s, String t) { int[] chars=new int[26]; for(int i=0; i<s.length(); i++){ chars[s.charAt(i) - 'a']++; } for(int i=0; i<t.length(); i++){ chars[t.charAt(i) - 'a']--; } for(int i=0;...
Can you solve this real interview question? Find the Difference - You are given two strings s and t. String t is generated by random shuffling string s and then add one more letter at a random position. Return the letter that was added to t. Exampl
leetcode 389. Find the Difference 问题描述 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was a......
impl Solution { pub fn find_the_difference(s: String, t: String) -> char { s // 转成字节切片 .as_bytes() // 转成迭代器 .iter() // 串上 t 的字节迭代器 .chain(t.as_bytes().iter()) // 使用 fold 积累 ans ,初始为 0 , // 对每个字符都执行异或操作, // 这样最后的值就是...
Find the letter that was added in t. Example: Input: s = "abcd" t = "abcde" Output:e Explanation: 'e' is the letter that was added. 将字符串s洗牌,在插入一个字符,得到字符串t,求这个插入的字符。 class Solution { public: char findTheDifference(string s, string t) { vector<int> co...
class Solution: def findTheDifference(self, s: str, t: str) -> str: return chr(reduce(operator.xor, map(ord, s + t), 0)) class Solution2: def findTheDifference(self, s: str, t: str) -> str: return chr(sum(map(ord, t)) - sum(map(ord, s))) ...
Can you solve this real interview question? Find the Distinct Difference Array - You are given a 0-indexed array nums of length n. The distinct difference array of nums is an array diff of length n such that diff[i] is equal to the number of distinct el
LeetCode之Find the Difference 1、题目 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t....
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