此解法的时间复杂度是O(n),空间复杂度是O(1)。 publicchar findTheDifference3(String s, String t) {intch=0;for (inti=0; i<s.length(); i++) {ch=ch^s.charAt(i);} for (intj=0; j<t.length(); j++) {ch=ch^t.charAt(j);} return (char)ch;} 05 第四种解法 此解法思路和第三...
java解法如下:public class Solution { public char findTheDifference(String s, String t) { int[] chars=new int[26]; for(int i=0; i<s.length(); i++){ chars[s.charAt(i) - 'a']++; } for(int i=0; i<t.length(); i++){ chars[t.charAt(i) - 'a']--; } for(int i=0;...
389. Find the DifferenceEasy Topics Companies You are given two strings s and t. String t is generated by random shuffling string s and then add one more letter at a random position. Return the letter that was added to t. Example 1: Input: s = "abcd", t = "abcde" Output: "e" ...
impl Solution { pub fn find_the_difference(s: String, t: String) -> char { s // 转成字节切片 .as_bytes() // 转成迭代器 .iter() // 串上 t 的字节迭代器 .chain(t.as_bytes().iter()) // 使用 fold 积累 ans ,初始为 0 , // 对每个字符都执行异或操作, // 这样最后的值就是...
Find the letter that was added in t. Example: Input: s = "abcd" t = "abcde" Output:e Explanation: 'e' is the letter that was added. 将字符串s洗牌,在插入一个字符,得到字符串t,求这个插入的字符。 class Solution { public: char findTheDifference(string s, string t) { vector<int> co...
import operator from functools import reduce class Solution: def findTheDifference(self, s: str, t: str) -> str: return chr(reduce(operator.xor, map(ord, s + t), 0)) class Solution2: def findTheDifference(self, s: str, t: str) -> str: return chr(sum(map(ord, t)) - sum(ma...
LeetCode -- 389. Find the Difference 题目Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was add......
leetcode卡两个仅由小写字母组成的字符串s和t。字符串t由随机打乱字符串s生成,然后在随机位置再添加一个字母。找到在t中添加的字母。 例子: 输入:s = \"abcd\" t = \"abcde\" 输出:e 解释: 'e'是添加的字母。文件列表 FindDifference-master.zip (预估有个2文件) FindDifference-master findThe...
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https://leetcode.com/problems/find-the-difference/ public class Solution { public char findTheDifference(String s, String t) { char[] sch = s.toCharArray(); char[] tch = t.toCharArray(); Arrays.sort(sch); Arrays.sort(tch); for (int i=0; i<sch.length; i++) { ...