Find the Difference 问题: Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter
impl Solution { pub fn find_the_difference(s: String, t: String) -> char { s // 转成字节切片 .as_bytes() // 转成迭代器 .iter() // 串上 t 的字节迭代器 .chain(t.as_bytes().iter()) // 使用 fold 积累 ans ,初始为 0 , // 对每个字符都执行异或操作, // 这样最后的值就是...
class Solution { public: char findTheDifference(string s, string t) { vector<int> count(128, 0); for(char ch : s){ count[ch]++; } for(char ch : t){ count[ch]--; } for(char ch = 'a'; ch <= 'z'; ch++){ if(count[ch] != 0){ return ch; } } return ' '; } }...
解题代码: ## LeetCode 389E Find the difference from typing import List class Solution: def findTheDifference(self, s: str, t: str) -> str: c = 0 ## 用 0 和 s 中的每个字母进行异或运算 for l in s: c = c ^ ord(l) ## ord 转换为 ASCII print(c) ## 打印中间临时结果 ## ...
LeetCode389Find the Difference找不同 给定两个字符串 s 和 t,它们只包含小写字母。 字符串 t 由字符串 s 随机重排,然后在随机位置添加一个字母。 请找出在 t 中被添加的字母。 示例: 输入: s = "abcd" t = "abcde" 输出: e 解释: 'e' 是那个被添加的字母。
389. Find the DifferenceEasy Topics Companies You are given two strings s and t. String t is generated by random shuffling string s and then add one more letter at a random position. Return the letter that was added to t. Example 1: Input: s = "abcd", t = "abcde" Output: "e" ...
LeetCode -- 389. Find the Difference 题目Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was add......
Explanation: 'e' is the letter that was added. 1. 2. 3. 4. 5. 6. 7. 8. 9. please: Input: s = "a" t = "aa" Output: a 2、代码实现 public class Solution { public static char findTheDifference(String s, String t) { ...
leetcode卡两个仅由小写字母组成的字符串s和t。字符串t由随机打乱字符串s生成,然后在随机位置再添加一个字母。找到在t中添加的字母。 例子: 输入:s = \"abcd\" t = \"abcde\" 输出:e 解释: 'e'是添加的字母。文件列表 FindDifference-master.zip (预估有个2文件) FindDifference-master findThe...
代码: class Solution { public: char findTheDifference(string s, string t) { string::iterator itr; for(int j=0;j<t.size();j++) { itr = find(s.begin(),s.end(),t[j]); if(itr==s.end()) return t[j]; else s.erase(itr);//将匹配到的字母删除 ...