Find the derivative of f(x)=tanx at x=0. View Solution BANSAL-LIMITS AND DERIVATIVES-All Questions Find the derivative of y=(1- ln\ x)/(1+ ln\ x) 02:24 Find the derivative of y=(x^3+2^x)/(e^x) 03:20 Find the de
Thus, the derivative ofy=xsinxwith respect toxis: dydx=xcosx+sinx Find the derivative of the following functions (it is to be understand... 03:16 Find the derivative of the following functions (it is to be understand... 01:25
Find the derivative \frac{dy}{dx}. y = (x^3 + 2x)^{37} Find the derivative y=(2sinx)^2. What is the derivative of \ln(\sin x + \cos x) Find the derivative: y = \frac{\cos\theta}{1 + \sin^{2}\theta} Find the indicated derivative \frac{dy}{dx} for y=x^3+ \sin...
For example; the derivative of the function f(x)=x is f′(x)=1 and the derivative of the function f(x)=sinx is f′(x)=cosx and so on. Answer and Explanation: The given function is: F(x)=∫04xsin(t)dt To determine th...
百度试题 结果1 题目Find the derivative of each of these functions.(sinx)/x 相关知识点: 试题来源: 解析 (xcosx-sinx)/(x^2 反馈 收藏
lnx∴y' = -y(1 + lnx)3)两边取对数:lny = xcosx两边对x求导:y'/y = cosx - xsinx∴y' = y(cosx - xsinx)4)两边取对数:lny = √x·ln(lnx)两边对x求导:y'/y = [ln(lnx)]/(2√x) + √x·(1/lnx)·(1/x)∴y' = y·{[ln(lnx)]/(2√x) + √x·(1/lnx)·(1/x)}...
y=(sin(x)−cos(x))2 Differentiate using the chain rule, where f(x)=x2 and g(x)=sin(x)−cos(x). 2(sin(x)−cos(x))ddx[sin(x)−cos(x)] By the Sum Rule, the derivative of sin(x)−cos(x) with ...View the full ...
A) Use the Chain Rule to find the derivative off(x)=x2+sin2x. B) Use the Chain Rule to find the derivative off(x)=sin(cos(tanx2)). Differentiation These questions are from the differentiation and we ha...
Find dydx if y=sec−1x2. Chain Rule: The chain rule is arguably the most important of all of our differentiation rules. Direct applications of it include our methods for implicit differentiation as well as related rates, among other things. To find the derivative of the function above...
Use the rules of differentiation to find the derivative of the function.y=1+9sin(x) y'(x)= 相关知识点: 试题来源: 解析 (dy)/(dx)=d/(dx)(1+9sinx) y'(x)=d/(dx)(1)+d/(dx)(9sinx) =0+9d/(dx)(sinx) =9cosx 反馈 收藏 ...