Find the compositions of the following functions: f(x) = x and g(x) = 5x + 2. Find (fg)(25) Composite Function: In a composite function, the output from a function is made an input to the other function. In other words, the range of a function be...
Find the composite function f(g(x)) given f(x)=2x^2-x \text{ and } g(x)=3x-1. Given two functions f(x) = 3x + 4 and g(x) = \frac{1}{3}(x-4), find f(g(x)) and g(f(x)). Given the following functions: f(u)=u^{5...
Find each composite function and describe the domain of the resulting function.a. f° g b. g° fc. f° f d. g° ga. (f° g)(x)=▱ (Simplify your answer.)相关知识点: 试题来源: 解析 a. (f° g)(x)=81x , x≥q 0 ...
【题目】h(x)=arcsin(x) z∈Rg(x)=1/x x∈R. z≠q0Find an expression for the composite functionh o g(z) and state is domain. 相关知识点: 试题来源: 解析 【解析】hog(x)=arctan(1/x)domain ofho g is equalto the domain ofg:∈o,x≠0 ...
The function is a composite function. There are three terms of which only have a variable and the remaining two are simple constants. The differentiation of constant is zero. Here, we need to apply the power rule of differentiation. The following formula of differentiation will be app...
(2) Find the derivative of the function y=49−x2 Chain Rule for Derivatives: The first function will be evaluated by the chain rule for derivatives. Chain rule for derivatives is used for composite functions. The formula for the chain rule for deriv...
Set up the composite result function. ( f(g(x))) Evaluate( f(g(x))) by substituting in the value of ( g) into ( f). ( f(x^2-1)=√((x^2-1)+1)) Add ( -1) and ( 1). ( f(x^2-1)=√(x^2+0)) Add ( x^2) and ( 0). ( f(x^2-1)=√(...
【解析】Set up the composite result function.f(g()Evaluatef(g(z) by substituting in the value ofg into f.f(x^2-1)=√((x^2-1)+1) Add -1 and 1.f(x^2-1)=√(x^2+0) Add 2 and o.f(x^2-1)=√(x^2) Pull terms out from under the radical, assuming positiv...
3. Given the function f: x→2x-3 and composite function fg :x→6x^2-4x+1 .Find(a)g(x),(b) the value of gf(-1).[4 marks]Answer :(a)(b) 相关知识点: 试题来源: 解析 f^(-1)(f(g(x))=f^(-1)(6x^2-4x+1) 反馈 收藏 ...
“设函数y=f(u)的定义域为Du,值域为Mu,函数u=g(x)的定义域为Dx,值域为Mx,如果Mx∩Du≠Ø,那么对于Mx∩Du内的任意一个x经过u;有唯一确定的y值与之对应,则变量x与y之间通过变量u形成的一种函数关系,这种函数称为复合函数(composite function),记为:y=f[g(x)],其中x称为自变量,u为中间变量,y为因...