百度试题 结果1 题目Find the area of the surface.The part of the cone that lies between the plane y=x and the cylinder 相关知识点: 试题来源: 解析反馈 收藏
How do you find the surface area of a cone given the volume is 150 cm^3? If the volume of a square cylinder is 128 pi cm^3 what are its dimensions? When the volume of a gas changes very rapidly, an approximate relation is that the pressure (P...
9) Find the surface area of this regular pyramid. 10) Find the volume of this regular pyramid. 10 9 11) This cylinder has a base area of 9 . What is its volume? h = 10 12) Find the surface area of this triangular prism. 13) Find the volume of this triangular prism 14)Find...
Find the area of the region cut from the paraboloid {eq}x^2 + z^2 - y = 0 {/eq} by the planes {eq}y = 2 {/eq} and {eq}y = 6. {/eq} Surface Area: In this we will convert the equation as function {eq}y=f(x,z) {/eq} and to solve ...
Find the area of the surface. The portion of the cone z = 2*sqrt(x^2 + y^2) inside the cylinder x^2 + y^2 = 4. Find the surface area of the part of the cone z = \sqrt{x^2 + y^2} that lies under the plane z = R. Do ...
Example 3: Find the volume of the ice-cream as shown in the image. Solution: The diameter of the top of the cone is 2 inches. Therefore, the radius of the top will be \(\frac{2}{2}\) = 1 inch. V = \(\frac{1}{3}\pi r^2h\)[Formula for volume of a cylinder] ...
A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps. The area of the sheet required to make 10 such caps is ...
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To find the slant height of a cone, we make use of a formula that is derived from the Pythagorean theorem, the radius of the cone, and the altitude of the cone. Answer and Explanation: If a cone has a radius (r) and altitude (h), then we find the slant height (s), using the...
clc clear fprintf('This program will determine the surface area and volume of a right circular cone,\na cylinder, and a rectangular prism. \n \n'); a = 1; while a == 1 n = input('How many objects would you like to find the surface area...