( y=-x^2+2) The area of the region between the curves is defined as the integral of the upper curveminus the integral of the lower curve over each region. The regions are determined by the intersectionpoints of the curves. This can be done algebraically or graphically. ( Area=(∫ ...
Find the area bounded by the curvesx=∣∣y2−1∣∣andy=x−5 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
Step 4: Set up the integral for the areaThe area A enclosed between the curve and the line from x=−1 to x=2 can be expressed as:A=∫2−1((−x−2)−(−x2))dxThis simplifies to:A=∫2−1(x2−x−2)dx Step 5: Calculate the integralNow we will calculate the in...
the x-axis and expressing x=y^2 as y=√ x and y=-√ x. Intersection points: 4=y^2 ⇒ y=± 2.\begin{split}A&=\int ^{2}_{-2}(4-y^{2})\d y=\left[4y-\dfrac {y^{3}}{3}\right]^{2}_{-2}\\&=\left(4(2)-\dfrac {2^{3}}{3}\right)-\left(4(-2)-\d...
Answer to: Find the area of the region between the curves y=x and y=x^{(1/3)} By signing up, you'll get thousands of step-by-step solutions to your...
Answer to: Find the area between the curve y = tan x and the x-axis from x = -\pi/4 to x = \pi/3. By signing up, you'll get thousands of...
Answer to: A) Find the area enclosed by the curves y1(x) = 5x - x^2 and y2(x) = x. B) Now find the volume when the region above is rotated around...
Find the area of the region enclosed by the curves y=x and 2x+y2=24.The Area Between Two Function:We will be using the horizontal slice method to find the area of the bounded region. We'll find the point of intersection of the two given curves so that we get the limi...
Find the area bounded by the linesy=3x,y=15-3x,and thexaxis. Find the area bounded by the parabolay=6+4x-x2and the chord joining(-2,-6)and(4,6). Find the area bounded by the parabolasy2=2xandx2=2y. ...
Find the area of the region bounded by the curves y=x , y=1/(x^2) , and x=2 I know after you sketch it you have to take the intergral of the top function minus the bottom function from the points that they intersect. I am stuck however because one function ...