Find the angle between the lines vec r=2 hat i-5 hat j+ hat k+lambda(... 04:31 Let f:WvecW , be defined as f(x)=x-1 , if x is odd and f(x)=x+1 , if x... 09:59 Using properties of determinants, prove that |[a+x,y,z],[x,a+y,z],[x,y... 03:17 x=acos...
To find the angle between the lines given by the equations 7x−y=1 and 6x−y=11, we will follow these steps: Step 1: Convert the equations to slope-intercept formWe need to express both equations in the form y=mx+b, where m is the slope. 1. For the first line 7x−y=1: ...
【题目】Consider the lines L:(x/z)-(2/(1-3))+λ(1/2) and M:)-()…()where A. u ∈ R.Find the acute angle between the lines L and M.Find a vector n that is perpendicular to both lines.Find an equation of the plane P that contains the line Land which is perpen...
A) Find a unit vector normal to the plane 2x-y+z=6. B) Find a set of parametric equations of the line through the point (1, -2, 3) and orthogonal to the plane x-4y+2z=0. C) Find the angle between the How to find a vector normal to another vector?
Ex.1 Find the acute angle between lines having slopes 3 and -2. 相关知识点: 试题来源: 解析 Solution : Let and .Let \theta be the acute angle between them.The acute angle between lines having slopes 3 and -2 is . 反馈 收藏
I can't do much with this since you didn't supply BW. But anyway, I don't know what it does but I never use bwtraceboundary(). I always get boundaries with bwboundaries() because it is much easier. Would that work for you?
To find the angle between two curves intersecting in a point, we will calculate the angle between the tangent vectors to the curve at the common point. If we are interested in the acute angle of intersection, then we will take the positive argument of inverse cosine function: {eq}\...
Thus the point of intersection is (π4,(√ 2)2). We have (π4,(√ 2)2) and (π4,(√ 2)2), so the tangent lines at that point have slopes (√ 2)2 and - (√ 2)2. Vectors parallel to the tangent lines are 1, (√ 2)2 and 1,- (√ 2)2, and the angle θ between...
Answer to: Find the area between the curve y = tan x and the x-axis from x = -\pi/4 to x = \pi/3. By signing up, you'll get thousands of...
The curves y=x^2 and y=x^3 meet when x^2=x^3⇔ x^3-x^2=0⇔ x^2(x-1)=0⇔ x=0, x=1. We have x=1 and x=1, so the tangent lines of both curves have slope 0 at x=0. Thus the angle between the curves is 0^(° ) at the point (0,0). For x=1, (0,0...