FIND(find_text, within_text, [start_num]) FINDB(find_text, within_text, [start_num]) 中文字符等会识别为2位 返回的是 要查找的内容在字符串内的位数。 局限性 区分大小写,不允许通配符 如果在VBA中使用,记得字符串,是需要"" 表达的 也是模糊查询 Sub test501() Debug.Print WorksheetFunction.Find(...
Find word(s) within a text string that match a list of keywords. (VBA) In previous threads, the answer has been to use the search() function. This works well, but I was wondering how this could be done in a VBA macro? Register To Reply +...
如果，楼主的意思是在VBA中用函数查找字符串，那么既可以用VBA内置函数Instr，也可以用Excel表函数Find()Instr("我们是中国人"，“中国")WorksheetFunction.Find("中国","我们是中国人")都将返回4 不同的是，在找不到时，Instr返回0，而Find返回一个错误1004 ...
For Each rng In .Range("B1:E20")If rng.Text Like "*a*" Then .Range("A" & a) = rng.Text a = a + 1 End If Next End With End Sub 代码截图：代码解读：上述过程使用For Each...Next语句和Like运算符在单元格区域B1:E20中搜索含有“a”字符的单元格，找到匹配单元格以后将单元格的值写入...
VBA Len functionreturns the length of a string: MsgBox Len("XBCX")'Result is: 4 VBA Right functionreturns n characters from the end of a string: MsgBox Right("ABCDE",2)'Result is: DE We can use InStrRev function to find the last occurrence of “\” in the pathname and use Len fun...
VBA常用的文本函数 instr、mid、find InStr 函数 Tips:在Visual Basic中,字符串的默认比较方法是vbBinaryCompare(二进制比较),它是区分大小写的。如果你想进行不区分大小写的比较,可以使用vbTextCompare(文本比较)。 DimSearchString, SearchChar, MyPos SearchString ="XXpXXpXXPXXP"' String to search in.Search...
但是如果string或pattern 中有一个为Null,则result 为 Null。 下面我们通过一个实例来讲解,先看下面的代码: Sub mynz_8_2() '8 利用FindPrevious方法进行重复搜索和利用LIKE查找 Dim rng As Range Dim a As Integer a = 1 With Sheets("8") .Range("A:A").ClearContents For Each rng In .Range("...
Use start_num to skip a specified number of characters. Using Find as an example, suppose you are working with the text string AYF0093.YoungMensApparel. To Find the number of the first "Y" in the descriptive part of the text string, set start_num equal to 8 so that the serial-...
VBA Coding Made Easy Return nth Word in String of Text The following function will find the nth word in a string: FunctionFind_nth_word(PhraseAsString,nAsInteger)AsStringDimCurrent_PosAsLongDimLength_of_StringAsIntegerDimCurrent_Word_NoAsIntegerFind_nth_word=""Current_Word_No=1'Remove Leading...
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