UserfindMethod to Find Substring in a String in C++ rfindmethod has a similar structure asfind. We can utilizerfindto find the last substring or specify a certain range to match it with the given substring. #include<iostream>#include<string>using std::cin;using std::cout;using std::endl ...
c++ string 我做了一个c++字符串,它将使用find和substring命令分成子字符串,并且一直存在子字符串多于指令的问题。它们应该是没有数字的句子。 #include <iostream> #include <algorithm> #include <string.h> using namespace std; int main() { string questions = "1. pog 2. pog2 3. pog3 4. pog4"...
#include <string> #include <iostream> int main () { using namespace std; string strSample ("this is a test"); size_t nOffset = strSample.find ("test", 0); // Check if the substring was found... if (nOffset != string::npos) cout << "found:" << nOffset; else cout <<...
// g++ -g -o x x.cpp #include #include extern "C" int main() { std::string::size_type n = std::string::npos; std::string str = "123"; std::string::size_type m = str.find("2", n); // 按照期望,m值应为npos std::cout << "n=" << n << ", m=" << m << st...
find('%')) != std::string::npos) { // Permit uppercase letters, lowercase letters and numbers in macro names const auto after = to_search.find_first_not_of("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789", pos + 1); // Now to_search[pos] == '%' and to_search[...
find characters in the view (public member function) rfind find the last occurrence of a substring (public member function) find_first_of find first occurrence of characters (public member function) find_first_not_of find first absence of characters (public member function) ...
string::find( char c, size_type pos = 0 ) returns the index of the first occurrence of c in the string beginning at index pos. string::substr( size_type pos = 0, size_type n = npos ) returns the substring of n characters beginning from, and including, the character at index 'pos...
The substring with start index = 2 is "ab", which is an anagram of "ab". 要完成的函数: vector<int> findAnagrams(string s, string p) 说明: 1、给定一个字符串s和非空字符串p,将p中元素不断交换形成一个新的字符串,如果这个新的字符串在s中能找到匹配的,那么就输出匹配到的开始的位置,直到处...
string fullname = "Mark Tompkin", firstname, lastname; int index; index = str.find_last_of(' '); // index is 4 // firstname = "Mark" lastname = "Tompkin" firstname = fullname.sub string(0,index); lastname = fullname.substring(index+1); ...
cout << "The index of the 'x' found in str1 is: " << indexCh1b << endl << endl; else cout << "The character 'x' was not found in str1." << endl << endl; // The second member function searches a string // for a substring as specified by a C-string string str2 ( ...