include <conio.h> int main(){ char src[1001] = {0};char sub[20] = {0};void findSubString(char src[],char sub[]);printf("Input the string: ");gets(src);//输入字符串 gets(sub);findSubString(src, sub);return 0;} void findSubString(char src[],char sub[]){ int ...
1 Finding all instances of a substring in a string 1 C string functions 1 Finding a substring 1 C - Find substring in a formatted string 0 Find sub-string in string 2 Finding substring in a string 1 Finding a substring within a string in C 0 Find all substrings of a strin...
find(str3.c_str(), pos, length) != string::npos ? cout << length << " chars match from pos " << pos << endl : cout << "no match!" << endl; return EXIT_SUCCESS; } Output: 6 chars match from pos 0 Use rfind Method to Find Substring in a String in C++ rfind method...
maxDeviation = 0; n = strlen(str); for i = 0 to n { if(n-i < maxDeviation) break; //this is new stop point to improve sub1 = substring(str,i,n); sub2 = substring(str,0,n-i); // you can use if(i!=0) to avoid duplication of first sentence a = findMaxDeviation(sub1...
std::cout << "Substring not found.\n"; } return 0; } 性能差别: <algorithm>头文件下的find()函数和string类的find()函数在查找字符串中的字符时,它们的运行速度和性能差别通常不大。 这两个函数都是线性查找算法,它们的时间复杂度都是O(n),其中n为字符串的长度。它们都需要遍历整个字符串,直到找到目...
; size_t found = str.find("World"); if (found != string::npos) { cout << "Substring found at position: " << found << endl; } else { cout << "Substring not found." << endl; } 这段代码中,我们使用.find函数在字符串str中查找子字符串"World"。如果找到了该子字符串,函数会返回...
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You are given a number of case-sensitive strings of alphabetic characters, find the largest string X, such that either X, or itsinverse(相反,倒转)can be found as a substring of any of the given strings. Input The first line of the input file contains a single integer t (1 <= t <=...
* @brief Find position of a C substring. * @param __s C string to locate. * @param __pos Index of character to search from. * @param __n Number of characters from @a s to search for. * @return Index of start of first occurrence. ...
int find(const string &s, int pos = 0) const;//从pos开始查找字符串s在当前串中的位置 //查找成功时返回所在位置，失败返回string::npos的值 int rfind(char c, int pos = npos) const;//从pos开始从后向前查找字符c在当前串中的位置 int rfind(const char *s, int pos = npos) ...