百度试题 结果1 题目Find sin 0. cos 0. and tan 0 for each of the following values of 0.Simplify the expression V4- x2 as much as possible after substituting 2 sin 0for x. 相关知识点: 试题来源: 解析 21cosθ| 反馈 收藏
Sine, cosine and tangent, often shortened to sin, cos, and tan in mathematical operations and on calculator keys, are the most basic trigonometric functions. All three are based on the properties of a triangle with a 90-degree angle, also known as a right triangle. By knowing the sides of...
Answer to: Find sin (x/2), cos (x/2), and tan (x/2) from the given information: tan x = 1, 0 degrees less than x less than 90 degrees. By signing...
Find sin 4 and cos 4 if tan theta = 3 Find \cos x and \sin x if \tan x = 4. Find sin x if tan x = 3/4 cos 0 = -3/7 and 180^{\circ}<0<270^{\circ} find sin, tan, and sec Find the exact value of 2 sin (pi / 3) - 3 tan (pi / 6). If tan 2 = 4/3...
Given {eq}\displaystyle \cos x = \frac{1}{3}{/eq}, Find {eq}\sin x{/eq} and {eq}\tan x{/eq} if {eq}x{/eq} lies in the interval {eq}\displaystyle \big[\frac{\pi}{2},0 \big]{/eq} Trigonometry: Trigonometry is a branch of mathematics which is used to s...
To find the values of sin(α−β), cos(α−β), and tan(α−β) given cosα=−1213 and cotβ=247, we will follow these steps: Step 1: Determine sinαGiven cosα=−1213 and knowing that α is in the second quadrant, we can find sinα using the identity:sin2α+cos2α...
Find (i) sin C (ii) cos C and (iii) tan C in the adjacent triangle. 01:57 In triangle XYZ, angle Y is right angle , XZ =17cm and YZ =15 cm then ... 01:55 In a triangle PQR with right angle at Q , the value of angle P is ... 03:27 Find the values of cosec 60 ...
COS COSH DEGREES RADIANS SIN SINH TAN TANH 版权 FIND FIND 函数可返回一个字符串在另一个字符串中的开始位置。 FIND(待搜索字符串, 来源字符串, 开始位置) 待搜索字符串: 要查找的字符串值。 来源字符串: 要搜索的字符串值。 开始位置: 可选数字值,指定应该在指定字符串中开始操作的位置。
【题目】If a is an acute angle and sin o - 3. find cos a and tan o. 相关知识点: 试题来源: 解析 【解析】 $$ \cos \alpha = \frac { \sqrt { 5 } } { 5 } , \tan \alpha = \frac { 2 } { \sqrt { 5 } } $$
【题目】Find si nt,cost,tant,sect,csct,andcottwhent=π/(3) . 相关知识点: 试题来源: 解析 【解析】 sinπ/3=(√3)/2 n V3 cosπ/3=1/2 coS 1 y 2 tanπ/3=√3 secπ/(3)=2 cscπ/3=(2√3)/3 2V3 = 3 cotπ/3=(√3)/3 反馈 收藏 ...