Write a NumPy program to create a 5x5 array with random values and find the second-largest value in each column. Sample Solution: Python Code: importnumpyasnp# create a 5x5 array with random valuesnums=np.random
Given an array, we have to find the second largest number in the array using the class and object approach. Example: Input: array[0]:1 array[1]:2 array[2]:44 array[3]:3 array[4]:5 Output: Second Largest Number is 5 C++ code to find the second largest number in the array usin...
1if__name__=='__main__':2n =int(input())3arr =map(int, input().split())4print(sorted(list(set(arr)))[-2])
// Scala program to find the second largest element // from the array object Sample { def main(args: Array[String]) { var IntArray = Array(10,50,40,20,30) var count:Int=0 var large1:Int=0 var large2:Int=0 large1=IntArray(0) while(count<IntArray.size) { if (large1 < Int...
Write a Scala program to find the second largest element from a given array of integers.Sample Solution: Scala Code:object Scala_Array { def main(args: Array[String]): Unit = { var my_array = Array(10789, 2035, 1899, 1456, 2013,1458, 2458, 1254, 1472, 2365,1456, 2165, 1457, ...
"%.2f is the largest number.", n3); return 0; } Run Code Here, we have used 3 different if statements. The first one checks whether n1 is the largest number.The second and third if statements check if n2 and n3 are the largest, respectively....
So A[0] is the first element of the one-dimensional array A, and B[2, 1] is the second element in the third row of the two-dimensional array B:Python >>> A[0] # First element of A 3 >>> A[4] # Fifth and last element of A 5 >>> A[-1] # Last element of A, ...
Below is the JavaScript program to find the third maximum number in an array ?Open Compiler const arr = [1, 5, 23, 3, 676, 4, 35, 4, 2]; const findThirdMax = (arr) => { let [first, second, third] = [-Infinity, -Infinity, -Infinity]; for (let el of arr) { if (el ...
Having this program: n1=int(input("Enter first number: ")) n2=int(input("Enter second number: ")) if n1 less than n2: for i in range(n2,n2+1): print(i) if n1==n2; print(n1) if n1 greater than n2: Write a while loop in Python that prints user_num divided by 2 until use...
Enter first number 23 Enter second number 1 Enter third number 10 Largest number is 23 Here in the above code, we takes three integer numbers from the user using the readLine() function that are num1 = 23, num2 = 1 and num3 = 10. Now using the max() function we compare all the...