Find all roots of the equation,including complex roots.Bingpei Wu
Find all real roots of the equation (x= + 4)(2x − 1) = (x= + 4)(2x + 1) by a method that involves factoring. [ Show all work.] 相关知识点: 试题来源: 解析 ∅, There are no real rootsWORK SHOWN: (x= + 4)(2x − 1) = (x= + 4)(2x + 1), (x= + 4)(2x...
(ii)Find all the roots of the equation z^(10)+z^5+1=0 ,giving each root in the form eie.[5] 相关知识点: 试题来源: 解析 3(ii) z^5=-1/2+i(√3)/2 z^5=erp(i2π(1/3+k)(i2π(-1/3+k)) exp(±t(2π)/(15),exp(t+(4π)/(15))⋅exp(t+(2π)/3),exp...
View Solution letz1,z2,z3andz4be the roots of the equationz4+z3+2=0, then the value of4∏r=1(2zr+1)is equal to : View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium
Hence the equation in the question becomes y^5-(32)(y^5)=31, i.e. (y^5-32)(y^5+1)=0. It follows that y may be 2 or -1. ●If x+2+√(x^2+4x+3) =2, we have x^2+4x+3 = (-x)^2, which gives x=-34. ●If x+2+√(x^2+4x+3) =-1, we have x^2+4x+...
Find the roots of the equationx+1x=3,x≠0 View Solution Find the roots of the following equations: x−1x=3,x≠0 View Solution Find the roots of the following equations : x−1x=3,x≠0 View Solution Find the roots of the equationx+1x=3,x≠0 ...
相关知识点: 试题来源: 解析 N+1=cos(2n)/6π+2sin(2n)/6π, 3.o.s =0,-1/2±1/2(√3,-3/2±1/2i W2Uses the 6th roots of unity.Al for 3 correct roots.A1 Gives all six roots of the equation inexact form. 反馈 收藏
结果1 题目 f(z)=z^2+5z+10Find the roots of the equation f(z)=0, giving your answers in the form a± ib, where a and b are real numbers. 相关知识点: 试题来源: 解析 z=- 52+ (√ (15))2i and z=- 52- (√ (15))2i 反馈 收藏 ...
Formula to Find Roots of Quadratic Equation The term b2-4ac is known as the discriminant of a quadratic equation. The discriminant tells the nature of the roots. If discriminant is greater than 0, the roots are real and different. If discriminant is equal to 0, the roots are real and ...
百度试题 结果1 题目求以下方程的根之和. Find the sum of roots of the following equation. √25+x2−√145−x2=x 相关知识点: 试题来源: 解析 12−2√5. 反馈 收藏