1. Problem Descriptions:Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value.If target is not found in the array, return [-1…
输入:nums = [1,5,8,9] target = 7 输出:[-1,-1] 解决思路:二分查找直到找到第一个目标值,再对目标值左右进行二分查找 Python代码: classSolution(object):defsearchRange(self, nums, target):""":type nums: List[int] :type target: int :rtype: List[int]"""l=0 r= len(nums)-1whilel...
last= len(nums) - 1found=False results= [-1, -1]ifnums ==[]:returnresultsiftarget < nums[0]ortarget >nums[last]:returnresultswhilefirst <= lastandnotfound: mid= (first + last) // 2 #找到了,分别继续向前,向后查找,直到找到第一个和最后一个targetiftarget ==nums[mid]: low=mid hig...
This article mainly introduces how to find the position of an element in a list using Python, which is of great reference value and hopefully helpful to everyone. How to Find the Position of an Element in a List Problem Description Given a sequence containing n integers, determine the position...
return [-1, -1] while low<=high: mid = (low+high)//2 if nums[mid]==target: break elif nums[mid]<target: low = mid+1 else: high = mid-1 if nums[mid]==target: mid_low = mid mid_high = mid while nums[mid_low]==target: ...
在上面的示例中,我们定义了一个数组numbers,然后使用array.find()方法查找第一个满足条件(即为偶数)的元素。回调函数(element) => element % 2 === 0用于判断元素是否为偶数,如果是,则返回该元素。 array.find()方法还有其他用法,例如可以使用箭头函数以外的函数作为回调函数,也可以指定回调函数的this值。此外,...
题目描述 Given an array of integersnumssorted in ascending order, find the starting and ending position of a giventargetvalue. Your algorithm's runtime complexity must be in the order ofO(logn). If the target is not found in the array, return[-1, -1]. ...
[LeetCode] 34. Find First and Last Position of Element in Sorted Array 2019-11-04 12:18 −Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value. If target is not found ... ...
Python Find String in List usingcount() We can also usecount()function to get the number of occurrences of a string in the list. If its output is 0, the string is not present in the list. l1=['A','B','C','D','A','A','C']s='A'count=l1.count(s)ifcount>0:print(f'{...
Python Code: # Define a function to find the kth largest element in a list using quickselect algorithmdefquickselect(lst,k,start=0,end=None):# If 'end' is not specified, set it to the last index of the listifendisNone:end=len(lst)-1# Base case: If the 'start' position is great...