Find the points on the given curve where the tangent line is horizontal or vertical. r=e^(θ ) 相关知识点: 试题来源: 解析 horizontal tangents at (e^(π (n- 1/4)),π (n- 14)).vertical tangents at (e^(π (n+ 1/4)),π (n+ 14
Find the points on the given curve where the tangent line is horizontal or vertical. r=e^(θ ) 相关知识点: 试题来源: 解析 horizontal tangents at (e^(π (n- 1/4)),π (n- 14)). vertical tangents at (e^(π (n+ 1/4)),π (n+ 14))....
Find the points on the given curve where the tangent line is horizontal or vertical. (Assume 0≤θ<π) r=2cosθ.The Tangent of Polar Graphs:As it is known that tangent is a straight line which touches at just one...
Find the points on the given curve where the tangent line is horizontal or vertical. {eq}r=e^\theta {/eq} Horizontal and Vertical Tangents: You have to use the standard formula to find the slope of a polar curve. Then, for horizontal tangent, use the fact...
Find all points on {eq}\displaystyle x^2 - xy + y^2 = 1 {/eq}, find an expression for {eq}\dfrac {dy}{dx} {/eq} in terms of both {eq}x {/eq} and {eq}y {/eq} and find all points where the tangent l...
Find the Horizontal Tangent Line y=cos(x) ( y=(cos)(x)) 相关知识点: 试题来源: 解析 Set( y) as a function of ( x). ( f(x)=(cos)(x)) The derivative of ( (cos)(x)) with respect to ( x) is ( -(sin)(x)). ( -(sin)(x)) Set the derivative equal to ( 0) th...
( y=((4-x^(2/3)))^(3/2)) ( y=-((4-x^(2/3)))^(3/2)) Set( y) as a function of ( x). ( f(x)=((4-x^(2/3)))^(3/2),-((4-x^(2/3)))^(3/2)) Since ( =0), the equation will always be true. Always true The horizontaltangentlines on functi...
Find all points on the curve {eq}{y^2} + \ln \left( {x + {y^2}} \right) - x - 3 = 0 {/eq} where the tangent line is horizontal. Derivatives: A derivative tells us the slope of the tangent line to a curve at a point, and so hor...
Find the slope of the tangent line to f(x) = sin x at the Point ( -π/6, -1/2 ) of the graph. Find the points on the given curve where the tangent line is horizontal or vertical, r = 4 + 3 \sin \...
Because the tangent line will be horizontal at a maximum or minimum point of a curved function, it will have a slope of zero. This fact is sometimes used to find maxima and minima of functions, because their first derivative will be zero at those points. ...