Answer to: Find the point on the curve y = x^2 closest to the point (1/2, 5/4). By signing up, you'll get thousands of step-by-step solutions to...
Answer to: Find the point on the curve y = sqrt(x) that is closest to the point (3, 0). By signing up, you'll get thousands of step-by-step...
Find the coordinates of points on the curve y=2x^2 which are the closest to the point (0,2).Leave the answer in surd form. 答案 翻译出来就是 求 抛物线 y=2x^2 上的一点,到点(0,2).的距离最短.可以设点为(x,2x^2), 由点到点距离公式得距离L 的平方=4X^4-7X^2+4, 令t=x^2...
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Find a point on the curve y=x^3-3x where tangent is parallel to the chord joining (1,-2) and (2,7).
Answer to: Find the point on the plane 4x + 7y + 8z - 19 = 0 closest to the point (-2, 1, 3). By signing up, you'll get thousands of step-by-step...
I have a line and a curve, i want to make a... Learn more about perpendicular, point, intersect
相关知识点: 试题来源: 解析 \begin{array}{l} \frac{\mathrm{d} y}{\mathrm{d} x}=2 x-\frac{16}{x^{2}} \\ \text { When } \frac{\mathrm{d} y}{\mathrm{d} x}=0, \\ x=2, y=12 \end{array} 反馈 收藏
Find the point on the curve y = sqrt(x) that is closest to the given point (3, 0). Find the point on the curve Sqrt(x) that is closest to (0,3) Find an equation of the tangent line to the curve at the given point: y = sqrt(x...
Find the min distance and the index for that and then get the point on the other curve that is closest and take the midpoint of a line going from curve 1 to curve 2. Something like (untested): 테마복사 for k = 1 : length(x1) distances = sqrt((x1(k) - x2) .^ 2 +...