(ii) Find the equation of the perpendicular bisector of AB, giving your answer in the form y= mx +c,where m is given exactly and c is an integer.[4] 相关知识点: 试题来源: 解析 (ii)Mid-point (a, b)=(1/2their (i), 1) Gradient of AB leading to gradient of bisector, m ...
To find the equation of the perpendicular bisector of the line joining the points (1, 3) and (3, 1), we can follow these steps:Step 1: Identify the Points Let the points be: - A(1, 3) - B(3, 1)Step 2: Find the Mi
Question: Find the field on the perpendicular bisector, for r≫ℓ .Enter the x and y components of the field separated by a comma. Express your answer in terms of the variables Q , r , and appropriate constants...
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calculator maths mcqs class 8 maths mcqs class 9 maths mcqs class 10 maths mcqs class 11 maths mcqs class 12 maths mcqs lcm of 8 and 15 lcm of 8 and 15 is 120. the method to find the smallest possible multiple of two or more numbers is known as least common multiple. follow the ...
(ii) the equation of perpendicular bisector of the line segment AB. (iii) the value of ‘p’ of (-2, p) lies on it. View Solution Q2 Points A and B have coordinates (7,−3) and(1,9) respectively. Find the equation of the perpendicular bisector of the l...
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Tan θ = Perpendicular/ Base Alternatively, Tan θ = sin θ/cos θ Or Tan θ = 1/Cot θ Other formulas: Tan(-θ )=-Tanθ \(\begin{array}{l}Tan (x+y) =\frac{tan x +tan y}{1-tan x tan y}\end{array} \) \(\begin{array}{l}Tan (x-y)=\frac{tan x -tan y}{1+tan...