Find a peak element in this matrix. Return the index of the peak. Guarantee that there is at least one peak, andifthere are multiple peaks,returnany one of them. Example Example 1: Input: [ [1, 2, 3, 6, 5], [16,41,23,22, 6], [15,17,24,21, 7], [14,18,19,20,10], ...
由于题目中说,对于多个peak element,我们只需找到一个就可以了;同时,由于num[-1] = num[n] = -∞,因此数组中至少有一个peak element;那么设置begin、mid、end三个index分别指向数组的起始,中间和结尾: 1、如果num[mid] > num[mid + 1],说明在begin和mid 之间,至少存在一个peak element,因此只考察数组前...
162. Find Peak Element(重要) A peak element is an element that is greater than its neighbors. Given an input array wherenum[i]≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fin...
A peak element is an element that is greater than its neighbors. Given an input array wherenum[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fine. You may imagine thatnum[...
Explanation: Your function can return either index number 1 where the peak element is 2, or index number 5 where the peak element is 6. Follow up: Your solution should be in logarithmic complexity. 题目描述: 峰值元素是指其值大于左右相邻值的元素。
public int findPeakElement(int[] nums) { if (nums == null || nums.length == 0) return -1; if (nums.length == 1) return 0; return findPeakElement(0, nums.length - 1, nums); } private int findPeakElement(int begin, int end, int[] nums) { ...
Find Peak Element I A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fine. ...
Find Peak Element A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fine....
上菜 def findPeakElement(self, nums: List[int]) -> int: l, r = 0, len(nums)-1 while l < r: mid = l + (r-l) // 2 if nums[mid] > nums[mid+1]: # no overflow since l<r r = mid else: l = mid + 1 return l salut~编辑...
() + 1);}void main(){ vector<int>num; num.push_back(-2147483647-1);//不能直接push -2147483648 ,若这样,自动识别-2147483648为无符号的,不能将-号应用于无符号类型 cout << "The peak element`s index in num is " << findPeakElement(num) << endl; system("pause");}</int></int></...