A palindrome is a word, phrase, number, or other sequence of characters which reads the same backward as forward, such as madam. Write a java program to find the longest palindrome present in a given string. For example, in the string abcba, the longest palindrome is abcba and similarly ...
# Python program to find the# maximum frequency character in the string# Getting string input from the usermyStr=input('Enter the string : ')# Finding the maximum frequency character of the stringfreq={}foriinmyStr:ifiinfreq:freq[i]+=1else:freq[i]=1maxFreqChar=max(freq,key=freq.get)...
// C program to find the frequency of given word in a string #include <stdio.h> #include <string.h> int FindFrequency(char* str, char* word) { int len = 0; int wlen = 0; int cnt = 0; int flg = 0; int i = 0; int j = 0; len = strlen(str); wlen = strlen(word);...
How to convert Char Array to String in java Palindrome program in java Reverse number in java Java program to make simple calculator Java program to print Diamond pattern Java program to count number of words in sentence Java isLetter method Convert char to lowercase javaShare...
// 从c1, c2开始 向两侧展开,找到最长的palindrome// e.g. 如果已经知道 "aba"是字符串"cabac"的一个字串,palindrome,// 则向两侧展开时,"c" == "c", 即 s[l] == s[r],所以能够继续得到更长的palindromestringexpandAroundCenter(strings,intc1,intc2) ...
Given a string S, which consists of lowercase characters, you need to find the longest palindromic sub-string. A sub-string of a string S is another string S' that occurs "in" S. For example, "abst" is a sub-string of "abaabsta". A palindrome is a sequence of characters which rea...
题目给了我们两个string s 和 p, 让我们在 s 中 找到所有 p 的变位词。 利用两个HashMap 和 Sliding window: 先把p 的char 和 出现次数 存入 mapP; 然后遍历string s,利用 sliding window 把和 p 一样长度的 string 的 char 保存在 tempMap 里,比较 tempMap 和 mapP。
// Function to build a palindrome from a given stringconstbuild_Palindrome=(new_str)=>{letflag;// Variable to check if a palindrome is foundfor(leti=new_str.length;;i++){// Infinite loop starting from the length of the input stringflag=true;// Reset the flag for each iterationfor(le...
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string if (typeof str !== 'string') { // Return a message if the input is not a string return 'It must be a string.' } // Create a Map to store the occurrences of each character in the string const occurrence_Map = new Map() // Iterate through each character in the string ...