Scala Programming Array Exercise-22 with SolutionWrite a Scala program to find a missing number in an array of integers.Sample Solution:Scala Code:object scala_basic { def test(numbers: Array[Int]): Int = { var total_num = 0; total_num = numbers.length; var expected_num_sum = 0 ...
public static void main(String[] args) throws IOException { BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); String line; while ((line = in.readLine()) != null) { int[] nums = stringToIntegerArray(line); List<Integer> ret = new Solution().findDisappearedNumbers...
Given an array of integers where 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements of [1,n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returne...
We know that XOR of two equal numbers cancels each other. We can take advantage of this fact to find the missing number in the limited range array. The idea is to compute XOR of all the elements in the array and compute XOR of all the elements from 1 ton+1, wherenis the array’s ...
// C program to find the missing number in the array#include <stdio.h>intmain() {intarr[]={1,2,3,5,6};intsize=0;inti=0;intmissing=0; size=sizeof(arr)/sizeof(arr[0]); missing=(size+1)*(size+2)/2;for(i=0; i<size; i++) missing=missing-arr[i]; printf("Missing numbe...
publicList<Integer>findDisappearedNumbers(int[] nums){ List<Integer> list =newArrayList<Integer>();if(nums ==null|| nums.length <1) {returnlist; } Arrays.sort(nums);intindex = nums[0];if(index !=1) {for(intk=1; k<index; k++) { ...
Debug code in playground class Solution { public List<Integer> findDisappearedNumbers(int[] nums) { List<Integer> list = new ArrayList<Integer>(); for (int i = 0; i < nums.length; ++i) { int j = Math.abs(nums[i]) - 1;
publicList<Integer>findDisappearedNumbers(int[]nums){List<Integer>result=newArrayList<>();if(nums.length==0){returnresult;}Arrays.sort(nums);intlast=nums.length;intindex=0,i;for(i=1;i<=last&&index<last;){if(nums[index]==i){index+=1;i+=1;continue;}elseif(nums[index]<i){index++;...
def findDisappearedNumbers(self, nums: List[int]) -> List[int]: """Keypoint: how to take a flag at each position""" def way1(): for i, v in enumerate(nums): if nums[abs(v)-1] > 0: nums[abs(v)-1] *= -1 out = list() for i, v in enumerate(nums): if v > 0: ...
网址:https://leetcode-cn.com/problems/find-all-numbers-disappeared-in-an-array/ 题设:Given an array nums of n integers where nums[i] is in the range [1, n], return an array of all the integers in the range [1, n] that do not appear in nums. ...