A commonly asked puzzle at Java interviews is – finding the missing number from a series or array of numbers. This puzzle has been asked in an interview conducted on Amazon.com. 1. Problem In this Java puzzle, w have a series of numbers start (e.g. 1….N), and exactly one number...
理由原array作为hashtable来实现我们需要实现的东西 My code: // suppose 1-n in array with length n, one number missing, one number repeat oncepublicintfindMissingNumber(int[]nums){if(nums==null||nums.length<=1){return-1;}inti=0;intrepeatIndex=-1;while(i<nums.length){if(nums[nums[i]-...
Original array: 1, 2, 3, 4, 6, 7, Total items in the array: 6 Missing number of the said array: 5 Original array: 1, 2, 3, 4, 5, 6, 7, Total items in the array: 7 Missing number of the said array: 0 Scala Code Editor :...
// C program to find the missing number in the array#include <stdio.h>intmain() {intarr[]={1,2,3,5,6};intsize=0;inti=0;intmissing=0; size=sizeof(arr)/sizeof(arr[0]); missing=(size+1)*(size+2)/2;for(i=0; i<size; i++) missing=missing-arr[i]; printf("Missing numbe...
百度试题 结果1 题目Find the missing number: ( ). A: B: C: D: 相关知识点: 试题来源: 解析 C . ( ). ... . 故选.反馈 收藏
Given an array containsNnumbers of 0 ..N, find which number doesn't exist in the array. Example GivenN=3and the array[0, 1, 3], return2. Challenge Do it in-place with O(1) extra memory and O(n) time. 这道题是LeetCode上的原题,请参见我之前的博客Missing Number 丢失的数字。那...
publicclassSolution {/***@paramA: an array of integers *@return: an integer*/publicintfindMissing(int[] A) {//write your code hereintn =A.length;for(inti = 0;i< n;i++){while( A[i] !=i){if(A[i] <0 || A[i] >=n)break;inttmp =A[i]; ...
In int array from 0 to 10 {0,1,2,3,4,6,7,8,9} here 5 is missingReply Answers (6) My VS 2015 crashes on startup, what can be done ? collect variables About Us Contact Us Privacy Policy Terms Media Kit Sitemap Report a Bug FAQ Partners C# Tutorials Common Interview Questions ...
// Find the missing number in a given array intgetMissingNumber(intarr[],intn) { // Compute XOR of all the elements in the array intxor=0; for(inti=0;i<n;i++){ xor=xor^arr[i]; } // Compute XOR of all the elements from 1 to `n+1` ...
Find the missing number in the sequence:3,6,11,20,37,___,135.Answer:___. 答案 解:因为6=3×2-0;11=6×2-1;20=11×2-2;37=20×2-3;所以下个数应该为:37×2-4=70;验证:70×2-5=135正好是最后一个数;故答案为:70观察可以发现6=3×2-0;11=6×2-1;20=11×2-2;37=20×2-3...