In a right triangle, the adjacent side to θ is the side of the triangle that forms part of the angle θ but is not the hypotenuse. The opposite side to θ is the side that does not form part of the angle θ. To find one of the angles, choose the formula that can be used giv...
百度试题 结果1 题目 Triangle ABC is a right triangle where m∠ BAC is a right angle. Find the measure of each angle. 相关知识点: 试题来源: 解析 反馈 收藏
Problem 6: The measures of the sides of a right tri-angle are 60, 80 and 100. Find the measure of a line segment, drawn from the vertex of the right angle to the hypotenuse, that divides the triangle into two triangles of equal perimeters. (Fig. 48)A BD CFig. 48 ...
Answer to: If the measure of angle A = 70 degrees and the measure of angle B = 25 degrees, find the measure for angle C in the triangle of ABC. By...
Answer to: Consider the following triangle, where a = 53.5, \; b = 30.9. Find the measure of \angle A. By signing up, you'll get thousands of...
1. Measure the Length of the Ladder The ladder forms the hypotenuse of the right triangle. 2. Measure the Distance From the Ladder to the Wall This distance is the adjacent side when determining the angle the ladder makes with the ground. ...
Find the angle marked 0 in the triangle shown.25 cm e4cm 相关知识点: 试题来源: 解析 In this triangle, opposite =25 cmadjacent =4cmUsing tanθ=(OP|cosθ11)/(αdθ(α∫)tanθ=(25)/4=6.25Using a calculator gives θ=80.9°(to1d.p.) ...
What is the radius of a circle inscribed in a right angle triangle? Hence the radius of the inscribed circle is3. Here a and b are the sides and c is the hypotenuse of the right angled triangle. This is used when the circle is inscribed in a right angled triangle. ...
88)In triangle ABC, 4 A is right angle. If A B = 3 and AC = 4, find the value of sin B - cos C. d a. -4 b. 5 c.-3 d.0 相关知识点: 试题来源: 解析 dStep 1Since ∠A is right angleBC===5Step 2sinB-cosC=AC/BC-AC/BC=4/5-4/5= ...
Find the measure of angle A, if (2 sin A +1)(2 sin A-1)=0 01:41 The value of cos 2 theta in terms of cot theta is 01:57 The simplified value of sin^(4)alpha+cos^(4)alpha+(1)/(2) sin^(2) 2 al... 02:19 sqrt(((1+sin2theta))/(1-cos^(2)theta))["where" thet...