JavaScript Code: // Function to find the longest string(s) in an arrayfunctionlongest_string(str_ara){varmax=str_ara[0].length;// Initialize max length with the length of the first stringstr_ara.map(v=>max=Math.max(max,v.length));// Update max with the maximum length in the array ...
JavaScript Code:// Function to find the longest string in an array function longest_str_in_array(arra) { var max_str = arra[0].length; // Initialize max_str with the length of the first string var ans = arra[0]; // Initialize ans with the first string // Loop through the array ...
JavaScript实现-找出最长单词-Find the Longest Word in a String 找出最长单词 在句子中找出最长的单词,并返回它的长度。 函数的返回值应该是一个数字。参考String.split()和String.lengthfunction findLongestWord(str) { // 请把你的代码写在这里 var arr = str.split(" ");...
Array.prototype.splice() 代码 function findLongestWord(str) { // 分割字符串 var stringArr = str.split(" "); // 边界值及递归跳出条件 if (stringArr.length === 1) { return stringArr[0].length; } // 比较数组中第一个元素(字符串)与第二个元素(字符串)的长度 if (stringArr[0].length...
JavaScript 是一种动态类型语言,变量的类型无法在编译阶段确定,必须在运行时才能知道。而同时js的变量类型又可以随意改变,因此又属于弱类型语言 JS中的运算符对数据类型有要求。因此常常发生类型自动转换 强制类型转换主要指使用Number()、String()和Boolean()手动将任意类型的值,分别转换成数字、字符串或者布尔值。
String.length 第一种想法就是,先定一个小变量,来他一个0;然后把每个单词的长度与它比较,把长度大的赋值给该变量,最后返回该变量; functionfindLongestWord(str) {vararray=str.split(' ');//分割句子为单词,保存在数组array里varresult=0;//先定一个小目标for(vari=1;i<array.length;i++){//遍历单词...
Stringabulous! String Length Finder Examples Click to try! click me Find Length of a Short String This example finds the length of the string "foo baz baz". As you can quickly count, there are nine letters in it and two spaces, so the output is 11. foo bar baz 11 Required options...
Tool Options Find options Find this string String String to find Find this regular expression Regex Regular expression to match Replacement options New string New string What Is a String Replacer? This tool lets you find-and-replace strings in your browser. It finds substrings in the given strin...
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Since the array is increasing first & then decreasing so the maximum element would be the last one in the increasing series & the first one in the decreasing series. SO we can ignore the increasing part and check if the next element is decreasing or not. As soon as we fin...