In C# I need to write a program that prints in the console application the last digit of a particular number "n". ... n Result 21 1 139 9 4 4
firstDigit=(int)(number/(int)(Math.pow(10,digits))); System.out.println("First digit: "+firstDigit); } } Output Last digit: 7 First digit: 5 Using while loop and pow() method If we don’t want to uselog()method then usewhile loopto count the number of digits and use that cou...
Find last digit of a number with power First identify the pattern last digit (unit place) for power of numbers “N” Digit N1N2N3N4N5N6N7N8N9 111111111 248624862 397139713 464646464 555555555 666666666 793179317 842684268 919191919 From the above table we can observe as follow ...
若A=1+4+9+16+25+⋯+841+900+961,求A的最后一个数位的值. 相关知识点: 试题来源: 解析 6. 结果一 题目 【题目】Find the last digit of A ifA=1+[4+9+[4+4+9+4]+[16+25+⋯+84]+41+[90+96+1] .若 A=1+4+9+16+25+⋯+841+900+961 ,求A的最后一个数位的值 答案 ...
百度试题 结果1 题目【题目】Find the last digit of A ifA=1*2*2*3+3*4+⋯+2*3*7*2018.若 A=1*2+2*3+3*4+⋯+2017*2018 ,求A的最后一个数位的值 相关知识点: 试题来源: 解析 【解析】8. 反馈 收藏
A common exercise in number theory is to find the last digits of a large power, like 22009, without using a computer. 22009is a 605-digit number, so evaluating it by hand is out of the question. So how do you find its last digits — efficiently?
PS: I'm not sure, but I guess that if I had splitted the first digit of the number instead of the last, maybe I could achieve a solution like the original algorithm. Share Improve this answer Follow edited May 23, 2017 at 12:33 CommunityBot 111 silver badge answered Feb 26, 2...
答案 1. 相关推荐 1求(1+3+5+7+⋯+2015+2017)(2+4+6+⋯+2016+2018)的个位值.Find the last digit of (1+3+5+7+⋯+2015+2017)(2+4+6+⋯+2016+2018).
Find the Number With Even Sum of Digits using C - An integer number that can be completely divided by 2 is an even number. So in this article we are given the number n, and we need to find the nth number with an even sum of digits. The First five number
百度试题 结果1 题目(1984 Math League, Grade 5&6, Question #39) Find the last digit of 19831984( ). A.1 B.2 C.3 D.9 相关知识点: 试题来源: 解析 A