Python Code: # Define a function 'find_index' that takes a list 'nums' and a function 'fn' as input.deffind_index(nums,fn):# Use a generator expression to find the first index 'i' where 'fn(x)' is True for an element 'x' in 'nums'.returnnext(ifori,xinenumerate(nums)iffn(x...
封装# find_elementUtil.py import os import time from selenium.webdriver.support import expected_conditions as EC from appium.webdriver.common.appiumby
driver.find_element_by_xpath('//*[@id="kw"]').send_keys('袁冰妍') # 简单但是阅读性不太好 1. 2. 3. 4. find_element_by_css_selector:根据css选择器选择元素 # find_element_by_css_selector:根据css选择器选择元素 # 涉及前端的一些知识点,这个点.代表class #代表id driver.find_element_by...
10).until(EC.presence_of_element_located((By.TAG_NAME,'video')))# 再次尝试获取视频元素videos=driver.find_elements(By.TAG_NAME,'video')print(f"找到{len(videos)}个视频元素")exceptExceptionase:print(f"发生错误:{e}")finally:driver.quit()...
#例子:target='www.163.com'print(target.find('163'))iftarget.find('263')==-1:print('263不存在于字符串'+target+'中') 运行: C:\Users\horn1\Desktop\python\7>python find.py4263不存在于字符串www.163.com中 当然,如果仅仅是字符串里是否存在子串的话,使用 in 和 not in 操作符更好。
Here, we will create the example Python list of string values that will be used in the examples in this tutorial. So, in your Python programming IDE, run the code below to create the example Python list of strings:my_list = ["car", "radio", "wheels", "bicycle"] print(my_list) #...
element:当前元素。 index(可选):当前元素的索引。 array(可选):调用find的数组。 thisArg(可选):执行回调时用作this的对象。 示例代码 代码语言:txt 复制 const users = [ { id: 1, name: 'Alice' }, { id: 2, name: 'Bob' }, { id: 3, name: 'Charlie' } ]; // 查找id为2的用户 const...
This article mainly introduces how to find the position of an element in a list using Python, which is of great reference value and hopefully helpful to everyone. How to Find the Position of an Element in a List Problem Description Given a sequence containing n integers, determine the ...
const evenNumber = numbers.find((element) => element % 2 === 0); console.log(evenNumber); // 输出:2 在上面的示例中,我们定义了一个数组numbers,然后使用array.find()方法查找第一个满足条件(即为偶数)的元素。回调函数(element) => element % 2 === 0用于判断元素是否为偶数,如果是,则返回该...
np.logical_and(a>=7, a<=20): This line of code creates a boolean array of the same shape as a. It applies two element-wise conditions, checking whether each element in a is greater than or equal to 7 and less than or equal to 20. The result is a boolean array where each elemen...