Time Complexity: The time complexity of std::unordered_map::find() is crucial for understanding its efficiency: In the average case, the time complexity is constant (O(1)), making it highly efficient for typical use cases. In the worst-case scenario, the time complexity becomes linear (O(...
class Solution { public: vector<vector<string>> findDuplicate(vector<string>& paths) { unordered_map<string, vector<string>> m; vector<vector<string>> res; for (string& path : paths) { istringstream is(path); string pre = "", t = ""; is >> pre; while (is >> t) { int idx ...
Your runtime complexity should be less thanO(n2). There is only one duplicate number in the array, but it could be repeated more than once. 思路1使用map存储元素及其对应索引。 classSolution {public:intfindDuplicate(vector<int>&nums) {if(nums.empty())return0; unordered_map<int,int>m;for(...
index-1,map); } return; } // if the digit is seen before, replace it with the same character // used in the previous occurrence findCombinations(list,keys,combinations,map[digit]+result,index-1,map); } unordered_set<string>findCombinations(autoconst&lists,autoconst&keys) { // create a...
unordered_map<int,int>parent; public: // perform MakeSet operation voidMakeSet(intn) { // create `n` disjoint sets (one for each vertex) for(inti=0;i<n;i++){ parent[i]=i; } } // Find the root of the set in which element `k` belongs ...
for path in paths: roads = path.split() directory, files = roads[0], roads[1:] for file in files: file_s = file.split('(') name, content = file_s[0], file_s[1][:-1] full = directory + '/' + name filemap[content].append(full) ...
unordered_map<string, vector<string>>m;for(stringpath : paths) { istringstreamis(path);stringpre ="", t ="";is>>pre;while(is>>t) {intidx = t.find_last_of('(');stringdir = pre +"/"+ t.substr(0, idx);stringcontent = t.substr(idx +1, t.size() - idx -2); ...
// string::find_first_of#include <iostream>// std::cout#include <string>// std::string#include <cstddef>// std::size_tintmain () { std::string str ("Please, replace the vowels in this sentence by asterisks."); std::size_t found = str.find_first_of("aeiou");while(found!=std...
class Solution{public:vector<vector<int>>threeSum(vector<int>&nums){sort(begin(nums),end(nums));vector<vector<int>>r;unordered_set<string>v;unordered_map<int,int>index;for(inti=0;i<nums.size();++i){index[nums[i]]={i};}for(inti=0;i<nums.size();++i){if((i>0)&&(nums[i]=...
in Even Counts.// Time Complexity: O(s.length()).// Space Complexity: O(1).classSolution{public:intfindTheLongestSubstring(strings){staticunordered_map<char,int>vowels{{'a',0},{'e',1},{'i',2},{'o',3},{'u',4}};intans=0;intmask=0;// {mask, left-most idx}unordered_map<...