You can use the Pythoninoperator to check if a string is present in the list or not. There is also anot inoperator to check if a string is not present in the list. l1=['A','B','C','D','A','A','C']# string in the listif'A'inl1:print('A is present in the list')#...
with open("example.txt", "r") as file:content = file.read()# 在文件中查找子字符串position = content.find("Hello")# 输出结果if position != -1:(tab)print(f"'Hello' found at position {position}")else:(tab)print("'Hello' not found")本例中 首先，我们打开一个名为"example.txt"的...
Although this is probably a less elegant solution, using any() does allow you to have somewhat softer matching than the simple comprehension above - this is, however, risky, because if you have a string in the list that has at least your match criteria string, as well as more information,...
实例(Python 2.0+) #!/usr/bin/python str1 = "this is string example...wow!!!"; str2 = "exam"; print str1.find(str2); print str1.find(str2, 10); print str1.find(str2, 40);以上实例输出结果如下:15 15 -1实例(Python 2.0+) >>>info = 'abca' >>> print info.find('a')...
在上述代码中,我们首先使用find()方法找到第一个子串"is"的位置,然后使用find()方法从第一个子串之后的位置开始找到第二个子串"is"的位置。最后,我们打印出第二个子串的位置。 序列图 下面是使用mermaid语法绘制的序列图,展示了整个实现的过程: Beginner教授如何实现"Python string find 第二个"定义字符串和子串...
Learn how to find the index of a string in a Python list with easy-to-follow examples and explanations.
51CTO博客已为您找到关于python find in list的相关内容,包含IT学习相关文档代码介绍、相关教程视频课程,以及python find in list问答内容。更多python find in list相关解答可以来51CTO博客参与分享和学习,帮助广大IT技术人实现成长和进步。
输出结果为:PythongnStrgni综上所述:s.upper()输出结果为PYTHONSTRING;s.lower()输出结果为pythonstring;s.find('i')输出结果为7;s.replace('ing','gni')输出结果为PythongnStrgni。 对于给定的字符串`s`,我们可以按照所提供的操作一步步来分析每个操作的结果。
If a substring doesn't exist inside the string, it returns-1. Working of find() method Working of Python string's find() and rfind() methods Example 1: find() With No start and end Argument quote ='Let it be, let it be, let it be'# first occurance of 'let it'(case sensitive...
[]6iflength1 <length2:7return-18i =09whilei <= length1-length2:10ifsource[i] ==dest[0]:11dest_list.append(i)12i += 113ifdest_list ==[]:14return-115forxindest_list:16print("Now x is:%d. Slice string is :%s"% (x,repr(source[x:x+length2])),end="")17ifsource[x:x+...