To find the HCF (Highest Common Factor) and LCM (Lowest Common Multiple) of the numbers 404 and 96, and to verify that HCF × LCM = Product of the two numbers, we can follow these steps:Step 1: Prime Factorization of 404 To fin
To find the HCF (Highest Common Factor) and LCM (Lowest Common Multiple) of the numbers 404 and 96, we will use the Prime Factorization method. Let's go through the solution step by step.Step 1: Prime Factorization of 404 - Sta
This is the most basic method to find LCM and HCF. There are few other methods as well like ladder method, log division method, etc, I feel the method above is foolproof and there is least chance of committing mistakes.
Enter two numbers: 3 4 HCF = 1 LCM = 12 2nd run: 1 2 3 Enter two numbers: 210 45 HCF = 15 LCM = 630 How it works The following table demonstrates what happens at each iteration of the while loop in thecalculate_hcf()function, assuminglarger = 210andsmaller = 45: ...
解析 HCF is 9, LCM is 3510 结果一 题目 Find the LCM and HCF of 234 and 135. 答案 HCF is 9, LCM is 3510234=2×32×13135=33×5HCF is 32=9LCM is 2×33×5×13=3510相关推荐 1Find the LCM and HCF of 234 and 135.反馈 收藏 ...
百度试题 结果1 题目Find the LCM and HCF of 234 and 135.相关知识点: 试题来源: 解析 HCF is 9, LCM is 3510 反馈 收藏
using System; using System.Text; // Class RecExercise12 for finding GCD and LCM of two numbers class RecExercise12 { // Main method to execute the program public static void Main() { // Variables to store input numbers, GCD, and LCM long num1, num2, hcf, lcm; // Prompt for and...
百度试题 结果1 题目1. (a) Find the HCF of 42, 66 and 78.(b)Find the LCM of 9, 16 and 18. 相关知识点: 试题来源: 解析 1. (a) 6(b) 144 反馈 收藏
Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54. The LCM and HCF of i) 26 and 91, ii) 51...
prime factors prime factorisation of hcf and lcm real numbers for class 10 long division method in this method, the largest number among the given set of numbers should be divided by the second largest number, and again the second-largest number should be divided by the remainder of the ...