百度试题 结果1 题目(a) Find the gradient of the line with equation 3x +4y = 104y=10-3x or -4y=3x-10 相关知识点: 试题来源: 解析 4y=10-3x or -4y=3x-10 反馈 收藏
百度试题 结果1 题目Find the gradient of the curve with the equation y=3e^(-x) at the point (0,3). 相关知识点: 试题来源: 解析 -3 反馈 收藏
Capture.PNG this formul is very bad and i dont know type this for my data in matlab :| I spent 1 day typing this formula :( 댓글 수: 0 FEATURED DISCUSSION Tree topper: L-Shaped Membrane What better way to add a little holiday magic tha...
百度试题 结果1 题目Find the gradient and y-intercept of a line with equation:y = (3-2x)5 相关知识点: 试题来源: 解析 m = - 25, c= 35 反馈 收藏
5 Find the gradient of the line with equation 3y =x-4 相关知识点: 试题来源: 解析 http://gallery.fbcontent.cn/latex?decode=false&latex=%24%24%5Cbegin%7Baligned%7D%20%26y%3D%5Cfrac%7Bx-4%7D%7B3%7D%5C%5C%20%26%5Cfrac%7B-1-0%7D%7B4-1%7D%20%5Cend%7Baligned%7D%24%24%25&...
Find the gradient of the function {eq}\displaystyle g(x,y) = \frac{5y}{x^2 + 2} {/eq} at point (1,4). Then sketch the gradient together with the level curve that passes through the point. Gradient: ...
Find the equation of the circumcircle of the triangle ABC, where A=(3,1),B=(0,2) and C=(1,5).Give your answer in the form . 答案 First, find the centre of the circle. Do this by finding the perpendicularbisectors of any two sides:Midpoint of ,gradient of So the perpendicular...
Find the gradient of L.(2)Find the coordinates of the point where L crosses the y-axis.(3)Find an equation of the line that is parallel to L and crosses the x-axis at (-2,0) 相关知识点: 试题来源: 解析 (1)1.5(2)(0,-7.5)(3)y=1.5x+3 (1)N/A.(2)N/A.(3)N/A....
(b)Gradien from (3,1)to(7,4)=3/4(this is the normal) Gradient of tangent =-3/4Equatio is y-4=-3/4(x-7) or 3y+4x=40(c)B is centre of line joining centres→(11,7)Radius=5New equation is (x-11)^2+(y-7)^2=25(FT on coordinates of B) ...
题目 In each Question from 27 to 30, find(a)the gradient of the curve at the given point,(b) the equation of the tangent to the curve at that point,(c) the equation of the normal to the curve at that point.. y=x+e^x;x=1 相关知识点: 试题来源: ...