Use the slope( -3) and a given point( (2,5)) to substitute for ( x_1) and ( y_1) in the point-slope form( y-y_1=m(x-x_1)), which is derived from the slopeequation( m=(y_2-y_1)/(x_2-x_1)). ( y-(5)=(-3)(x-(2))) Simplify the equation and keep it i...
Simplify theequationand keep it inpoint-slope form. y−2=23⋅(x−1)y-2=23⋅(x-1) Solve foryy. Tap for more steps... Simplify23⋅(x-1). y-2=0+0+23⋅(x-1) y-2=23⋅(x-1) y-2=23x+23⋅-1 23andx.
Find the slope of the line between ( (7/3,-8)) and ( (7/3,1)) using ( m=(y_2-y_1)/(x_2-x_1)), which is the change of ( y) over the change of ( x). Undefined The slope of the line is undefined, which means that it is perpendicular to the x-axis at ( x=...
解析 Find the value of ( b) using the formula for the equation of a line.( b=-(49)/3)Now that the values of ( m) (slope) and ( b) (y-intercept) are known, substitute them into ( y=mx+b) to find the equation of the line.( y=7/3x-(49)/3)...
Step1 Find the equation of the line l. Begin by finding the slope of the line (-5,3) through points (-5,3) and (4,-6). m= (y_2-y_1)(x_2-x_1)= (-6-3)(4-(-5))= (-9)9 or -1Then write the equation of this line using the point (4,-6) on the line....
Find the equation of the line in point-slope form, and state the meaning of the slope in context-what information is the slope giving us? 相关知识点: 试题来源: 解析 y- 10=(35)2(x- 12); Every 2 in. of rainfall increases the number of cattle raised per acre by 35....
dy We know that slope of tangent to the curve y = f(x)at any point (x, y) is According to the given condition, we have (dy)/(dx)=x+xy dx 0r(dy)/(dx)-xy=x Which is a linear diffrential equation of the from (dy)/(dx)+Py=Q⋅|WheFe⋅ P=-r and Q+ rNow. IF=e...
百度试题 结果1 题目 2. Find the equation of the straight line whose slope is 3 and passes through the point (-1, 2) 相关知识点: 试题来源: 解析 3x - y + 5 = 0 反馈 收藏
Find the equation of the curve that passes through the point (1,3) and has a slope of at any point (x,y). 相关知识点: 试题来源: 解析 y 12 10 y=3e 6 4 y=3e^((x-1)) 2 (1,3) ⊕ X -2 2 4 6 8 10 反馈 收藏
Point slope form is y-y1 =m(x-x1) here m=4/3 (x1,y1) =(3.-2) y-(-2) =(4/3 )(x -3) y+2 =(4/3 )(x-3) 3(y+2) =4(x-3) 3y+6 =4x -12 standard form is 4x -3y -18 =0 Upvote • 0 Do...