解析 x+y=2. The direction vectors of the lines are (1,-1,2) and (-1,1,0), so a normal vector for the plane is(-1,1,0)* (1,-1,2)=(2,2,0) and it contains the point (2,0,2). Then an equation of the plane is 2(x-2)+2(y-0)+0(z-2)=0⇔ x+y=2....
解析 Given equation of plane is 3x+4y-5z= 0Equation of plane parallel to 3x+4y-5z= 0is given by3x+4y-5z+k= 0Since it passes through the point (1.2.3)3×1+4×2-5×3+k=03+8-15+k=0k-4substituent the value of the k we get3x+4y-5z+4=0 ...
Using this vector and one of the points we can find an equation of this plane. Answer and Explanation: Suppose that {eq}P(0,0,0),\, Q(3,-1,7) {/eq} and {eq}R(5,1,2) {/eq} are points on a plane. The vectors {eq}\vec{PQ}=<3-0,-1...
(a) Find the point at which the given lines intersect. r= (2,3,0) + t(3,-3,3) r= (5,0,3) + s(-3,3,0) (b) Find an equation of the plane that contains these lines. a) Find the point at which the...
Find the equation of the plane which bisects the line segment joining the points A(2,3,4)andB(4,5,8) at right angles. View Solution Find the equation of the plane which bisects the line segment joining the points (-1, 2, 3) and (3, -5, 6) at right angles. View Solution ...
百度试题 结果1 题目find an equation of the plane passing through the point perpendicular to the given vector or line.Point: (3,2,2)Perpendicular to: (x-1)4=y+2= (z+3)(-3) 相关知识点: 试题来源: 解析 4x+y-3z-8=0 反馈 收藏 ...
Find the equation of the plane: (1)with normal vector (bmatrix)2 -1 3(bmatrix) and through (-1,2,4) (2)perpendicular to the line through (2, 3, 1) and (5, 7, 2) and through (3)perpendicular to the line connecting (1,4, 2) and (4, 1, -4) and containing such that...
Answer to: Find an equation of the plane. The plane that passes through the point (1, -1, 1) and contains the line with symmetric equations x = 2 y...
Equations of Lines and Planes: Find an equation of the plane. The plane through the points (4,1,4),(5,−8,6),(−4,−5,1) Equation of the Plane: From the given three points, we can define two vectors Q0P0 and R0P0 through the giv...
Find the equation of the plane passes through the point(1,−3,1)and parallel to the plane2x+3y+z=1. Find the equations of the line passing through the point (-1, 2,1 ) and parallel to the line2x−14=3y+52=2−z3.